Step-by-step explanation:
Given

as equation 1.
I used q-p as the difference as logically the woman will be older than her son.
Also given,

as equation 2.
Using equation 2,

substitute this equation into equation 1.

Substitute P into equation 2.

Therefore the woman is 45 years old while her son is 15 years old.
<h3>
<u>Correct Question :- </u></h3>


(a) 0
(b) 8000
(c) 8080
(d) 16000

Given that

We know


And


Also, given that


and

Now, Consider





![\sf \: = 20\bigg[ {a}^{2} + {b}^{2} + {c}^{2} + {d}^{2}\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20%7Ba%7D%5E%7B2%7D%20%2B%20%20%7Bb%7D%5E%7B2%7D%20%2B%20%7Bc%7D%5E%7B2%7D%20%2B%20%20%7Bd%7D%5E%7B2%7D%5Cbigg%5D)
We know,

So, using this, we get
![\sf \: = 20\bigg[ {(a + b)}^{2} - 2ab + {(c + d)}^{2} - 2cd\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20%7B%28a%20%2B%20b%29%7D%5E%7B2%7D%20-%202ab%20%2B%20%20%7B%28c%20%2B%20d%29%7D%5E%7B2%7D%20-%202cd%5Cbigg%5D)
![\sf \: = 20\bigg[ {( - 20)}^{2} + 2(2020) + {(20)}^{2} - 2(2020)\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20%7B%28%20-%2020%29%7D%5E%7B2%7D%20%2B%20%202%282020%29%20%2B%20%20%7B%2820%29%7D%5E%7B2%7D%20-%202%282020%29%5Cbigg%5D)
![\sf \: = 20\bigg[ 400 + 400\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20400%20%2B%20400%5Cbigg%5D)
![\sf \: = 20\bigg[ 800\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20800%5Cbigg%5D)

Hence,

<em>So, option (d) is correct.</em>
35 is in the ten-thousandths place, so write it as a fraction over 10,000:
35/10000
Simplify:
7/2000
So we have:
3 7/2000 in mixed number form or 6007/2000 in improper fraction form.
Answer:
option 1
Step-by-step explanation:
if it goes up 6 then it means plus 6
Answer:
640 cm²
Step-by-step explanation:
The ratio of the area of 2 similar polygons = the ratio of the square of their corresponding lengths
Thus:
Area of Trapezoid ABCD to Area of Trapezoid EFGH = AB² to EF²
Area of Trapezoid ABCD = ? = x
Area of Trapezoid EFGH = 40 cm²
AB = 20 cm
EF = 5 cm
Substitute
x:40 = 20²:5²
x/40 = 400/25
x/40 = 16
Cross multiply
x = 16*40
x = 640
Area of trapezoid ABCD = 640 cm²