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3 years ago

Hi I was a little confused on dilation can anyone help me (will mark Brainly)

Mathematics

1 answer:

Westkost [7]3 years ago

7 0

Just divide the distance of each to point P by 2.

C would be 1 unit above and 2 units to the right of P.

D would be 1 unit below and 2 units to the right of P.

And so on...

Hope this helps

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A boat in still water is 32 mph. If the boat travels 72 miles upstream in the same time that it takes to travel 120 miles downst

dalvyx [7]

Dup= 72 miles
ddown= 120 miles 
v= riverspeed 
rup= 32mph - v 
rdown= 32mph + v 
t both ways= t 

d=r*t 
d/r=t 

t=ddown/rdown 
t=dup/rup 

dup/rup = ddown/rdown 

(72)/(32-v)=(120)/(32+v) 
3840-120v=2304+72v 
1536=192v 
v=8

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2 years ago

(1+cos2x)/(1-cos2x) = cot^2x

sesenic [268]

We will turn the left side into the right side.

$\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x$

Use the identity:

$\cos 2x = \cos^2 x - \sin^2 x$

$\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x$

$\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x$

Now use the identity

$\sin^2 x + \cos^2 x = 1$ solved for sin^2 x and for cos^2 x.

$\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x$

$\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x$

$\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x$

$\cot^2 x = \cot^2 x$

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3 years ago

Area of triangle with the base 8.4 height 8.56

Nikolay [14]

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Answer:

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Step-by-step explanation:

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Lesechka [4]

Answer:

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Step-by-step explanation:

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