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e-lub [12.9K]
3 years ago
7

I need help on 32 please

Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0
That is how you solve it

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Represent each of these relations on {1, 2, 3, 4} with a matrix (with the elements of this set listed in increasing order). a) {
Irina-Kira [14]

Answer:

for a  a) {(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)}

\left[\begin{array}{cccc}0&1&1&1\\0&0&1&1\\0&0&0&1\\0&0&0&0\end{array}\right]

for b

b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}

\left[\begin{array}{cccc}1&0&0&1\\0&1&0&0\\0&0&1&0\\1&0&0&0\end{array}\right]

for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}

\left[\begin{array}{cccc}0&1&1&1\\1&0&1&1\\1&1&0&1\\1&1&1&0\end{array}\right]

for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}

\left[\begin{array}{cccc}0&0&0&0\\0&0&0&1\\1&1&0&1\\0&0&0&0\end{array}\right]

Step-by-step explanation:

in matrix, arrays are placed in rows , which represents the horizontal sides from left to right, while arrays in the column are placed vertically from top to bottom. Here, we placed the arrays in a 4x4 matrix

for a  a) {(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)}

\left[\begin{array}{cccc}0&1&1&1\\0&0&1&1\\0&0&0&1\\0&0&0&0\end{array}\right]

for b

b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}

\left[\begin{array}{cccc}1&0&0&1\\0&1&0&0\\0&0&1&0\\1&0&0&0\end{array}\right]

for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}

\left[\begin{array}{cccc}0&1&1&1\\1&0&1&1\\1&1&0&1\\1&1&1&0\end{array}\right]

for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}

\left[\begin{array}{cccc}0&0&0&0\\0&0&0&1\\1&1&0&1\\0&0&0&0\end{array}\right]

7 0
3 years ago
Please help solve for PQ.
DerKrebs [107]
This problem cannot be solved unless we are given figure NPQR is a rhombus.
In that case, then all sides are equal, meaning 
5x+16=9x-32
Solve for x
9x-5x=16+32
4x=48
x=12

Each side (including PQ) then equals 5x+16=5*12+16=76
8 0
3 years ago
If ABC~DEF what is the length of BC?<br><br> If ABC~DEF what is the length of EF?
marysya [2.9K]

BC would equal the same as EF, they are similar. All you would have to do is figure out the pre image (BC) of EF.

3 0
3 years ago
Help me out!!
vekshin1

Answer:

~Exponential decay because the base is less than 1~

Step-by-step explanation:

I just took the test and got a 100% :) hope this helped! Good luck!

8 0
3 years ago
How do you put q fraction into a decimal
mafiozo [28]
It all depends on the fraction.

1/2=.5 because half of 1 is .5 and half can be represented as 2
8 0
3 years ago
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