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3 years ago

Find the value of x.

Mathematics

1 answer:

Tresset [83]3 years ago

4 0

Answer:

In the first problem, the value of x is 13.85

Step-by-step explanation:

To find this, we can use the Pythagorean Theorem. This allows us to use the length of the legs (a and b) to determine the length of the hypotenuse (c) .

a^2 + b^2 = c^2

5.3^2 + 12.8^2 = c^2

28.09 + 163.84 = c^2

191.93 = c^2

13.85 = c

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What is the value of y 4y squared-7y=15

zvonat [6]

Answer:

y= 3, (-5/4)

Step-by-step explanation:

4y^2-7y=15

4y^2 - 7y -15

(y-3)(4y+5)

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3 years ago

Riley wants to divide 30 flowers into 2 groups so that the ratio is 2 to 3

77julia77 [94]

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3 years ago

Equation for ( 6, 13) ( 7900, 5 )

tia_tia [17]

For this case we have that by definition, the equation of the line in the slope-intersection form is given by:

$y=mx+b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have the following points through which the line passes:

$(x_ {1}, y_ {1}) :( 6,13)\\(x_ {2}, y_ {2}): (7900,5)$

We find the slope of the line:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {5-13} {7900-6} = \frac {-8} {7894} = - \frac {4} {3947}$

Thus, the equation of the line is of the form:

$y = - \frac {4} {3947} x + b$

We substitute one of the points and find b:

$13 = - \frac {4} {3947} (6) + b\\13 = - \frac {24} {3947} + b\\13+ \frac {24} {3947} = b\\b = \frac {51335} {3947}$

Finally, the equation is:

$y = - \frac {4} {3947} x + \frac {51335} {3947}$

Answer:

$y = - \frac {4} {3947} x + \frac {51335} {3947}$

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3 years ago

Please assist me with the domain and range of graphs

Sphinxa [80]

Answer: see below

Step-by-step explanation:

Domain represents the x-values from the smallest (furthest left) to the biggest (furthest right).

Range represents the y-values from the lowest (furthest down) to the highest (furthest up).

Interval notation: If a value is included (closed dot), use a bracket [ ]

If a value is NOT included (open dot), use a parenthesis ( )

Note that ± ∞ is never included.

1. Domain: smallest x-value is -4 (included). biggest x-value is 3 (included)

Range: lowest y-value is 2 (included). highest y-value is 5 (included)

D: x = [-4, 3] R: y = [2, 5]

2. Domain: smallest x-value is -∞ (←). biggest x-value is 2 (included)

Range: lowest y-value is 2 (included). highest y-value is ∞ (↑)

D: x = (-∞, 2] R: y = [2, ∞)

3. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

Range: lowest y-value is -∞ (↓). highest y-value is ∞ (↑)

D: x = (-∞, ∞) R: y = (-∞, ∞)

4. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

Range: lowest y-value is -∞ (↓). highest y-value is 4 (included)

D: x = (-∞, ∞) R: y = (-∞, 4]

5. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

Range: lowest y-value is 3 (included). highest y-value is ∞ (↑)

D: x = (-∞, ∞) R: y = [3, ∞)

6. Domain: smallest x-value is -2 (included). biggest x-value is ∞ (→)

Range: lowest y-value is -3 (included). highest y-value is ∞ (↑)

D: x = [-2, ∞) R: y = [-3, ∞)

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3 years ago

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andrey2020 [161]

Short answer A
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A <<<<< answer

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3 years ago