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Bogdan [553]
2 years ago
5

7(x-3)+6=5x-9 please solve the equation fully

Mathematics
1 answer:
TiliK225 [7]2 years ago
4 0

Answer:

I love algebra anyways

The ans is x=3 steps is in the picture with the ans

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

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Consider the function f(x). Select all of the following that include a vertical stretch of f(x)
zhenek [66]

Answer:

F , D, A

Step-by-step explanation:

As we know vertical stretch of f(x)  happens when we chane the value of the patameter a in this general form:

y = a. f(k(x-d))+ c  

when  |a| > 1 because When |a| > 1 (when a is greater than 1), the function is stretched vertically by a dilation factor of |a|.

So we choose, F , D, A

4 0
3 years ago
Read 2 more answers
Solve for x: -3x + 3 &lt; 6<br> x&gt;-1<br> x&lt;-1<br> x&lt;-3<br> x&gt;-3
Triss [41]

Answer:

D is the correct answer

Step-by-step explanation:

first you subtract the 3 from the left side and add it to the right side. then you divide both side by negative 3 and flip the less than sign to a greater than sign

5 0
2 years ago
The graph above is a transformation of the function x2 Write an equation for the function graphed above
lutik1710 [3]

Answer: y=0,5x²-x-1,5.

Step-by-step explanation:

(-1;0)\ \ \ \ (3;0)\ \ \ \ (1;-2)   \ \ \ \  y=ax^2+bx+c\ ?\\\left\{\begin{array}{ccc}a*(-1)^2+b*(-1)+c=0\\a*3^2+b*3+c=0\\a*1^2+b*1+c=-2\end{array}\right \ \ \ \  \ \left\{\begin{array}{ccc}a-b+c=0\ \ (1)\\9a+3b+c=0\ (2)\\a+b+c=-2\ (3)\end{array}\right  \\

We summarize (1) and (3):

2a+2c=-2\ |:2\\a+c=-1\ \ \ \ \Rightarrow\\a+b+c=-2\\(a+s)+b=-2\\-1+b=-2\\b=-1.

Substitute b=-1 into (2):

9a+3*(-1)+c=0\\9a-3+c=0\\9a+c=3\ \ (5).\\

From (5) subtract (4):

8a=4\ |:8\\a=0,5.\ \ \ \  \Rightarrow\\

Substitute a=0,5 into (4):

0,5+c=-1\\c=-1,5.

Hense:

y=0,5x²-x-1,5.

5 0
1 year ago
What is 555.555 rounded to the nearest hundredth?
Misha Larkins [42]
600. Because 50 is rounded up.
4 0
3 years ago
Read 2 more answers
Determine if the given differential equation is exact (e^2y-y cos xy)dx+(2xe^2 y-cos xy+2y)dy=0
rewona [7]
\dfrac\partial{\partial y}\left[e^{2y}-y\cos xy\right]=2e^{2y}-\cos xy+xy\sin xy

\dfrac\partial{\partial x}\left[2xe^{2y}-y\cos xy+2y\right]=2e^{2y}+y\sin xy

The partial derivatives are not equal, so the equation is not exact.
7 0
3 years ago
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