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anastassius [24]

3 years ago

12

Y=2x-5, The slope is ............0 0D 22o -50 -3

2 answers:

pogonyaev3 years ago

5 0

Answer: 2

Step-by-step explanation:

The given equation is in slope-intercept form. It is y=mx+b. In this equation, m stands for slope and b stands for y-intercept. Looking back at the equation, we see that in place of m is 2. That tells us that the slope is 2.

Mama L [17]3 years ago

5 0

The slope is 2.

Remember:

• the formula for the equation of the line is
y = mx + b

Where m = slope, b = y-intercept, and x & y are coordinates

So if

y = mx + b
y = 2x - 5

The 2 is in place of the m which is the slope.

In other words, 2 = m = slope

Therefore, slope is 2.

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3 years ago

What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti

Marat540 [252]

Answer:

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

Step-by-step explanation:

Given

$x^2 - 5x - 7 = 0$

Required

Solve for x using:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

First, we need to identify a, b and c

The general form of a quadratic equation is:

$ax^2 + bx + c = 0$

So, by comparison with $x^2 - 5x - 7 = 0$

$a = 1$ $b = -5$ $c = -7$

Substitute these values of a, b and c in

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}$

$x = \frac{5 \± \sqrt{25 +28}}{2}$

$x = \frac{5 \± \sqrt{53}}{2}$

Split the expression to two

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

To solve further in decimal form, we have

$x = \frac{5 + 7.28}{2}$ or $x = \frac{5 - 7.28}{2}$

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Scorpion4ik [409]

The second choice is correct

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