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natima [27]
3 years ago
13

Can someone please help i posted this question already and it got ingored

Mathematics
1 answer:
coldgirl [10]3 years ago
3 0
The answer is C, since the number in the parenthesis represent what is being multiplied every year
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A right triangle has an area of 18 square inches.If the triangle is an isosceles triangle, what are the lengths of the legs of t
Gnom [1K]
If it is isosceles, than the legs are the same. We will call them X. The formula for the area of a triangle is 1/2 (base * height). But the base and the height are both X. So the area (18) is equal to 1/2 (x * x), or 1/2(x^2). This means that 36 = x^2. Thus, the length of each side is 6 inches. You can check this work by plugging those into the formula for area. You will find that it equals 18.
7 0
3 years ago
The graph of a function f(x) is shown below:<br><br><br><br> What is the domain of f(x)?
Pie

The domain is the scope of the x values. In this case (-2,-1) is a hole, so x>-2 is one end of the domain, while (3,3) is defined. So the domain using interval notation is (-2,3] which can also be expressed -2 < x ≤ 3, answer option 1

8 0
3 years ago
PLZ NEED HELP RIGHT AWAY
Sever21 [200]
1) A
3) B
4) A
5)A
sorry that i dont have all the answers, hope this helped
8 0
3 years ago
Read 2 more answers
Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or
soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

\lim_{x \to 3} f(x)

f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L

and the limit does not exist if

\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)

Evaluate the one-sided limits.

The left-hand limit

\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0

The right-hand limit

\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6

Because the limits are not the same the limit does not exist.

8 0
3 years ago
Jerry is trying to earn $209 for some new video games. If he charges $47 to mow a lawn, how many lawns will he need to mow to ea
Helen [10]
At least 5. because 47x4=188 which isn’t enough money, and 47x5=235, which goes over but you have to have more money than less money
6 0
3 years ago
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