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3 years ago

Can someone please help i posted this question already and it got ingored

Mathematics

1 answer:

coldgirl [10]3 years ago

3 0

The answer is C, since the number in the parenthesis represent what is being multiplied every year

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Geometric Shapes - Part 1

Softa [21]

Answer:

x = 54, so the vertical angles are 110°.

Step-by-step explanation:

$2x + 2 = 3x - 52$

$2 = x - 52$

$x = 54$

$2(54) + 2 = 108 + 2 = 110$

$3(54) - 52 = 162 - 52 = 110$

3 0

2 years ago

What does it mean to get a 150% salary raise? Explain in words and then give an example showing a calculation. pls and thx.

Simora [160]

if im correct its 50 more of the original amount.

example: if i make 100 a day , im now making 150 a day

3 0

3 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

3 years ago

Which would be appropriate compatible numbers to use to estimate ( 19 4 5 ) ( 4 6 ) ? Using this compatible number, what is the

MA_775_DIABLO [31]

The appropriate compatible numbers to use to estimate would be 20(1/2)

estimated product is 10, took the quiz :)

8 0

3 years ago

Lots of points plzzz help. What are m

lara31 [8.8K]

Answer:

???

Step-by-step explanation:

6 0

2 years ago