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insens350 [35]
3 years ago
10

A mosquito starts his flight in the air at 10 feet below sea level in a canyon. He then ascends to 18 feet above sea level. What

was the change in the height if his flight
Mathematics
2 answers:
Sladkaya [172]3 years ago
6 0
10-(-18)=28 because of the fact that below sea level is negative and above is positive
Ivahew [28]3 years ago
4 0

ascended 28 ft!

10 - (-18) = 28

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Law of sines: 2.2 units 2.4 units 3.0 units 3.3 units
Arada [10]

Answer:

RS=2.4\ units  

Step-by-step explanation:

<em>The complete question is </em>

What is the length of line segment RS? Use the law of sines to find the answer. Round to the nearest tenth.

see the attached figure to better understand the problem

step 1

Find the measure of angle S

Applying the law of sines

\frac{QS}{sin(R)}=\frac{QR}{sin(S)}

substitute the given values

\frac{3.1}{sin(80^o)}=\frac{2.4}{sin(S)}

Solve for sin(S)

sin(S)=\frac{sin(80^o)}{3.1}(2.4)

S=sin^{-1}[sin(80^o)}{3.1}(2.4)]

S=49.68^o

step 2

Find the measure of angle Q

Remember that the sum of the interior angles in any triangle mut b equal to 180 degrees

so

m\angle Q+m\angle R+m\angle S=180^o

substitute the given values

m\angle Q+80^o+49.68^o=180^o  

m\angle Q+129.68^o=180^o  

m\angle Q=180^o-129.68^o

m\angle Q=50.32^o

step 3

Find the length of segment RS

Applying the law of sines

\frac{QS}{sin(R)}=\frac{RS}{sin(Q)}

substitute the given values

\frac{3.1}{sin(80^o)}=\frac{RS}{sin(50.32^o)}

RS=\frac{3.1}{sin(80^o)}{sin(50.32^o)}  

RS=2.4\ units          

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