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zalisa [80]
3 years ago
6

Which of the following sets could be the sides of a right triangle? {2, 3, square root of 13} {2, 2, 4} (1, 2,square root of 3 }

Mathematics
1 answer:
ddd [48]3 years ago
8 0

Answer:

3545344534

Step-by-step explanation:

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Answer:

120 is the correct answer

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Passe os numeros a seguir para notação cientifica.
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masha68 [24]

Answer:

B) Multiply each side by 3

Step-by-step explanation:

This is how to solve for h

\frac{h}{3}+ 7 = 5           (First Step --> Subtract 7 from both sides)

\frac{h}{3} =  - 2             (Second Step --> Multiply both sides by 3 to cancel out the                                 denominator and to find just h)

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6 0
3 years ago
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Which equation represents the unit fraction shown in the diagram? A grid model with 100 squares. 20 squares are shaded.
hammer [34]

Answer:

A

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Expanding Logarithmic Expressions In Exercise, use the properties of logarithms to rewrite the expression as a sum, difference,
Leya [2.2K]

Answer:  \dfrac{1}{3}[\ln (x+1)+\ln(x-1)]

Step-by-step explanation:

Properties of logarithm :

  1. \log (ab)= \log a+\log b
  2. \log(\dfrac{a}{b})=\log a-\log b
  3. \log a^n= n\log a

The given expression in terms of Natural log : \ln (x^2 - 1)^{\frac{1}{3}}

This will become \dfrac{1}{3}\ln (x^2 - 1)      [ By using Property (3)]

=\dfrac{1}{3}\ln (x^2-1^2)

=\dfrac{1}{3}\ln ((x+1)(x-1))   [\because a^2-b^2=(a+b)(a-b)]

=\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]   [ By using Property (1)]

Hence, the simplified expression becomes \dfrac{1}{3}[\ln (x+1)+\ln(x-1)] .

5 0
3 years ago
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