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kvasek [131]
3 years ago
7

Plz help me quickly

Mathematics
1 answer:
Stels [109]3 years ago
6 0

Answer:

0

Step-by-step explanation:

according to what is given:

K = 0

N = 3

I = -2

so just substitute in these values into the given equations and solve

KN + IK

0 * 3 + -2 * 0

= 0 + 0

= 0

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Id- 6217974205 p/w-123​
andrey2020 [161]

Answer:

For what-

Step-by-step explanation:

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3 years ago
Read 2 more answers
4.One attorney claims that more than 25% of all the lawyers in Boston advertise for their business. A sample of 200 lawyers in B
AleksAgata [21]

Answer:

z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123  

p_v =P(Z>2.123)=0.0169  

The p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .  

Step-by-step explanation:

1) Data given and notation  

n=200 represent the random sample taken

X=63 represent the lawyers had used some form of advertising for their business

\hat p=\frac{63}{200}=0.315 estimated proportion of lawyers had used some form of advertising for their business

p_o=0.25 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that more than 25% of all the lawyers in Boston advertise for their business:  

Null hypothesis:p\leq 0.25  

Alternative hypothesis:p > 0.25  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.123)=0.0169  

The p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .  

8 0
3 years ago
hich equation represents a line that passes through (5, 1) and has a slope of ? y – 5 = (x –1) y – = 5(x –1) y – 1 = (x –5) y –
gtnhenbr [62]

Answer:

The equation that would represent it would be y - 1 = (x - 5)

Step-by-step explanation:

In order to get this, we can start with the base form of point-slope form.

y - y1 = m(x - x1)

Now put the point in for (x1, y1)

y - 1 = (x - 5)

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3 years ago
Write a two column proof given
never [62]
Im sorry but im not sure what your asking
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3 years ago
Find the value of x and y
elena55 [62]

Answer:

x=50 and y=20

Step-by-step explanation:

I hope this helped!

3 0
2 years ago
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