How much mass does 0.5 mole of barium contain?

In general, the solubility of ________ in water decreases as temperature increases.

Ghella [55]

Solubility of a gas in a liquid is directly proportional to the partial pressure of the gas present above the liquid and is inversely proportional to the temperature.

So, the solubility of <u>gas </u>in water decreases as the temperature increases.

7 0

3 years ago

Read 2 more answers

If you put a base in water , what will happen?

ohaa [14]

Answer:

It will dissociate:D

Explanation:

It's the correct answer

6 0

3 years ago

Water molecules are polar, with the Select one:

shusha [124]

Answer:

b. oxygen side being slightly negative and the hydrogen side being slightly positive.

Explanation:

The water molecule is a polar molecule, that is to say that its distribution of electronic density is different throughout the molecule.

In this way, in the water molecule there is a negative partial charge towards the oxygen atom and a positive partial charge towards the hydrogen atom.

This polar characteristic of the water molecule allows ions and other molecules to exhibit water solubility and is widely used in chemical reactions.

3 0

3 years ago

A reaction A(aq)+B(aq)↽−−⇀C(aq) has a standard free‑energy change of −4.20 kJ/mol at 25 °C. What are the concentrations of A, B,

Dafna1 [17]

Answer : The concentration of $A,B\text{ and }C$ at equilibrium are 0.132 M, 0.232 M and 0.168 M respectively.

Explanation :

The given chemical reaction is,

$A(aq)+B(aq)\rightleftharpoons C(aq)$

First we have to calculate the equilibrium constant for the reaction.

The relation between the equilibrium constant and standard free‑energy is:

$\Delta G^o=-RT \ln k$

where,

$\Delta G^o$ = standard free‑energy change = -4.20 kJ/mole

R = universal gas constant = 8.314 J/mole.K

k = equilibrium constant = ?

T = temperature = $25^oC=273+25=298K$

Now put all the given values in the above relation, we get:

$-4.20kJ/mole=-(8.314J/mole.K)\times (298K) \ln k$

$k=5.45$

Now we have to calculate the concentrations of A, B, and C at equilibrium.

The given equilibrium reaction is,

$A(aq)+B(aq)\rightleftharpoons C(aq)$

Initially 0.30 0.40 0

At equilibrium (0.30-x) (0.40-x) x

The expression of equilibrium constant will be,

$k=\frac{[C]}{[A][B]}$

$5.45=\frac{x}{(0.30-x)\times (0.40-x)}$

By solving the term x, we get

$x=0.168\text{ and }0.716$

From the values of 'x' we conclude that, x = 0.716 can not more than initial concentration. So, the value of 'x' which is equal to 0.716 is not consider.

The value of x will be, 0.168 M

The concentration of $A$ at equilibrium = (0.30-x) = 0.30 - 0.168 = 0.132 M

The concentration of $B$ at equilibrium = (0.40-x) = 0.40 - 0.168 = 0.232 M

The concentration of $C$ at equilibrium = x = 0.168 M

3 0

4 years ago

All of the following are abiotic factors in an ecosystem except:

vovangra [49]

The answer is Algae.

<span>Abiotic factors are non-living things of an ecosystem. Abiotic factors include landscape, climate, pH, salinity and other physical features of the ecosystem. On the other hand, there are b</span>iotic factors. Biotic factors are living things in the ecosystem. Those are plants, animals, and other organisms. Since Algae are living-things, they are biotic factors unlike pH, salinity, and climate which are abiotic factors.

8 0

4 years ago