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Assoli18 [71]
3 years ago
7

Find the eqation of the line perpendicular to y=3x-6 that runs through the point (-1, -3)

Mathematics
1 answer:
alexgriva [62]3 years ago
3 0
The coefficient of x in the equation of the given line, 3, is its slope. The slope of the perpendicular line is the negatve reciprocal of that, -1/3. You now have the slope and a point on the perpendicular line, so you can write its equation using the point-slope form:
  y = m(x -x₁) +y₁
where m is the slope and (x₁, y₁) is the point.

An equation for your perpendicular line is
  y = (-1/3)(x -(-1)) -3
  y = (-1/3)x -10/3

The slope-intercept form of the equation of the perpendicular line is ...
  y = (-1/3)x -10/3

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Three fifths of a number y is negative 9. What is the number?
klio [65]
\frac{3}{5}y=-9 \ |*5 \\\\ 3y=-45 \ |:3\\\\ y=-15
or
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3 years ago
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pashok25 [27]

Answer:

74 cm

Step-by-step explanation:

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Pleaseeeeee help !!
umka21 [38]

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4 0
3 years ago
Need someone to work this problem showing the steps
Dennis_Churaev [7]
Well first you would subtract 9 from both sides to isolate your variable
so it would look like
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so you're left with
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3 0
3 years ago
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trapecia [35]

Answer:

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Step-by-step explanation:

1. Simplify each term.

−4y+8−3y

2. Subtract 3y from −4y.

−7y+8

Hope this helps :D

3 0
2 years ago
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