2 NI₃= N₂ + 3 I₂
2 x 394.71 g --------------- 3 x 253.80 g
3.58 g ---------------------- ( mass of I₂ )
3.58 x 3 x 253.80 / 2 x 394.71 =
2725.812 / 789.42 => 3.4529 g of I₂
1 mole I₂ --------------- 253.80 g
?? ----------------------- 3.4529 g
3.4529 x 1 / 253.80 => 0.0136 moles of I₂
Answer C
hope this helps!
Answer:
a. qm = 627.3 J
b. qw = 627.3 J
c. C₂ = 227.4 J/kg.°C
Explanation:
a.
Since, the calorimeter is completely insulated. Therefore,
Heat Lost by Metal = Heat Gained by water
qm = qw
qm = m₁C₁ΔT₁
where,
qm = heat lost by metal = ?
m₁ = mass of water = (density)(volume) = (1000 kg/m³)(100 mL)(10⁻⁶ m³/1 mL)
m₁ = 0.1 kg
C₁ = specific heat capacity of water = 4182 J/kg.°C
ΔT₁ = Change in Temperature of Water = 19.1°C - 17.6°C = 1.5°C
Therefore,
qm = (0.1 kg)(4182 J/kg.°C)(1.5°C)
<u>qm = 627.3 J</u>
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b.
Since,
qm = qw
<u>qw = 627.3 J</u>
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c.
qm = m₂C₂ΔT₂
where,
m₂ = mass of metal = 38.1 g = 0.0381 kg
C₂ = specific heat capacity of metal = ?
ΔT₂ = Change in Temperature of metal = 90°C - 17.6°C = 72.4°C
Therefore,
627.3 J = (0.0381 kg)(C₂)(72.4°C)
(627.3 J)/(0.0381 kg)(72.4°C) = C₂
<u>C₂ = 227.4 J/kg.°C</u>
Answer:
electronegativity increases
Answer: The bond formed between the elements will be ionic bond.
Explanation: We are given two elements having electronic configurations:
Element 1: 
Element 2: 
Element 1 can easily loose 1 electron to attain stable electronic configuration and Element 2 can accept 1 electron to attain stable electronic configuration.
For these elements, there will be a complete transfer of electron from Element 1 to Element 2. Hence, this will form a ionic bond.
From the configuration, Element 1 is Lithium and Element 2 is Fluoride. So, the compound is LiF.
