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Ymorist [56]
3 years ago
8

When a reaction occurs between atoms with ground state electron configuration 1s2 2s1 and 1s2 2s2 2p5 the predominant type of bo

nd formed is
Chemistry
1 answer:
fenix001 [56]3 years ago
5 0

Answer: The bond formed between the elements will be ionic bond.

Explanation: We are given two elements having electronic configurations:

Element 1: 1s^22s^1

Element 2: 1s^22s^22p^5

Element 1 can easily loose 1 electron to attain stable electronic configuration and Element 2 can accept 1 electron to attain stable electronic configuration.

For these elements, there will be a complete transfer of electron from Element 1 to Element 2. Hence, this will form a ionic bond.

From the configuration, Element 1 is Lithium and Element 2 is Fluoride. So, the compound is LiF.

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Answer: Boyle's Law

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Boyle's Law is the pressure-volume law and it relates pressure and volume at constant temperature. Boyle's law states that pressure and volume vary inversely, meaning that as one goes up, the other one goes down.
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Binary Covalent (molecular) Compounds
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Explanation:

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2 years ago
In a reaction, chlorine accepts an electron to form Cl-. What is true about the atomic size of the chlorine ion?
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Answer is: The atomic size of the chlorine ion is larger than the size of the chlorine atom.

Covalent radii of chlorine atom (Cl) is 0.099 nm and ionic radii of chlorine anion (Cl⁻) is 0.181 nm.

Difference between an chlorine atom and chlorine anion is the number of electrons that surround the nucleus.

Chlorine atom has 17 electrons and chlorine anion has 18 electrons.

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3 years ago
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A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate
Zarrin [17]

Answer: Empirical formula is C_2H_5O

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

<u>Step 1 :</u> Converting each of the given masses into their moles by dividing them by Molar masses.

Moles=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = \frac{330g}{12g/mol}=27.5moles

Moles of Hydrogen = \frac{69.5g}{1g/mol}=69.5moles

Moles of Oxygen = \frac{220.2g}{16g/mol}=13.76moles

<u>Step 2: </u>Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2

\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5

\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1

<u>Step 3:</u> Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

Empirical formula becomes = C_2H_5O

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3 years ago
Which of the following statements about C3 carbon fixation is true? a. C3 carbon fixation is an adaptation for plants exposed to
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Answer: The answer is B

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