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m_a_m_a [10]
3 years ago
5

The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular fo

rmula and the empirical formula? a)<br /><br /> empirical formula mass / molecular mass = n<br /><br /> B) molecular mass = element mass / empirical formula mass ´ 100<br /><br /> c) subscript of H in empirical formula = 2  subscript of H in molecular formula<br /><br /> D) subscript of C in molecular formula = n  subscript of C in empirical formula<br /><br />
Chemistry
2 answers:
kobusy [5.1K]3 years ago
8 0
An empirical formula is the "reduced" version of a molecular formula. For example, CH3 is the empirical formula for C2H6, C3H9, C4H12, and so forth. The difference in subscripts between an empirical formula and molecular formula is given by the constant n. If n is a whole number, this means the numerator is the molecular formula. So the answer is D. <span>subscript of C in molecular formula = n  subscript of C in empirical formula. This can be rewritten as:

n = subscript of C in molecular formula/subscript of C in empirical formula</span>
balu736 [363]3 years ago
3 0

Answer:

The answer is D

Explanation:

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Identify whether each element is a halogen, a noble gas, or nonmetal only.
OLga [1]

Answer:

Astatine: Halogen

Nitrogen: Non-Metal

Krypton: Non-Metal, Noble Gas

Chlorine: Non-Metal

Sulfur: Non-metal

Explanation:

5 0
3 years ago
HELP ASAP! Chemical reactions involving liquids only will be influenced by ALL of the following EXCEPT: a) temperature of the sy
Rom4ik [11]
<span>Chemical reactions involving only liquids will be influenced by ALL of the following EXCEPT: </span><span><span>c) size of reactant particles d) pressure of the system.

</span>Reason:
1) As per Arrhenius theory, rate of chemical reactions is influence by temperature. Mathematically it is expressed as: k = A exp(-Ea/RT)
</span>where, k = rate constant, A = collision frequency, Ea = activation energy, T = temp. From above relation, it can be seen that, chemical reactions involving only liquids will be influenced temperature.

2) Also, if know that, rates of chemical reactions is mathematically expressed as: Rate = [A]^{x} B^{y}....,
where A, B, .. are the reactants.
From above relation, it can be seen that, chemical reactions involving only liquids will be influenced concentration i.e. number of particle. 

3) However, since all the reactant and catalyst used (if any) is in liquid state, particle size of same  will not influence the reaction.

4) Also, since there are no gas-phase reactant, pressure will not affect the reaction. 
8 0
2 years ago
How many molecules of nitrogen gas are in 22.4 L?
Serhud [2]
The answer is letter (B).
3 0
3 years ago
Read 2 more answers
PLSSS HELP FAST
Aliun [14]

Note the formula

\boxed{\sf Mass\:no=No\:of\:protons+No\:of\:neutrons}

For X:-

  • No of protons:-

\\ \sf\longmapsto 19-10=9protons

  • It is Fluorine.

For Y:-

  • No of protons:-

\\ \sf\longmapsto 16-8=8protons

  • It is Oxygen.

Option D is correct

7 0
2 years ago
A cylinder with a moveable piston contains 92g of Nitrogen. The external pressure is constant at 1.00 atm. The initial temperatu
Jobisdone [24]

Answer:

Work done in this process = 4053 J

Explanation:

Mass of the gas = 0.092 kg

Pressure is constant = 1 atm = 101325 pa

Initial temperature T_{1} = 200 K

Final temperature T_{2} = 200 - 85 = 115 K

Gas constant for nitrogen = 297 \frac{J}{kg k}

When pressure of a gas is constant, volume of the gas is directly proportional to its temperature.

⇒ V ∝ T

⇒ \frac{V_{2} }{V_{1} } = \frac{T_{2} }{T_{1} } ------------ ( 1 )

From ideal gas equation P_{1} V_{1} = m R T_{1} ------ (2)

⇒ 101325 × V_{1} = 0.092 × 297 × 200

⇒ V_{1} = 0.054 m^{3}

This is the volume at initial condition.

From equation 1

⇒ \frac{V_{2} }{0.054} = \frac{200}{115}

⇒ V_{2} = 0.094 m^{3}

This is the volume at final condition.

Thus the work done is given by W = P [V_{2} - V_{1} ]

⇒ W = 101325 × [ 0.094 - 0.054]

⇒ W = 4053 J

This is the work done in that process.

7 0
2 years ago
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