Answer:
See Explanation Below
Step-by-step explanation:
Given
Total Sweets = 10
Red = 4
Green = 2
Yellow = 3
Purple = 1
Required
a & b
The question is not properly presented; however the solution is as follows;
A.
Let P(Yellow) represent the probability of selecting a yellow sweet and n(Yellow) represent the number of Yellow sweets;



So, whichever letter that shows
or
is the probability of choosing a yellow sweet
B.
Let P(Orange) represent the probability of selecting an orange sweet and n(Orange) represent the number of orange sweets;
Since, there's no orange sweet in the bag;




In probability; opposite probabilities add up to 1;
Let P(Not\ Orange) represent the probability of choosing a sweet that is not orange

Substitute 


So, whichever letter that shows 0 is the probability of choosing a sweet that is not orange
Answer:
The second one or B- "He did not find the prime factors of 4."
Step-by-step explanation:
I got it right on Edge2020
c + 9 - 3(c - 10) > 1
We're going to treat this like a regular algebraic equation, thus most algebraic rules and properties apply.
First, apply distributive property.
c + 9 <u>- 3c + 30</u> > 1 (two - signs cancel out, creating a + sign.)
Combine like terms.
<u>-2c + 39</u> > 1
Subtract 39 from both sides.
-2c > <u>-38</u>
Divide both sides by -2.
<u>c < 19</u> (Because we're dividing by a negative number, the sign gets swapped.)
<h3>Your answer is c < 19.</h3>
The formula is V = (4/3) pi * r^3
r = 10 cm^3 = 1000 cm^3 That let's out D
V = (4/3) * 3.14 * 1000
V = (1.3333) * 3.14 * 1000
V = 1333 * 3.14
V = 4185 cm^3
A <<<< ==== answer