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Law Incorporation [45]
3 years ago
15

1. Which of the following represents a function?

Mathematics
2 answers:
trapecia [35]3 years ago
7 0
1. 3rd one, because for each x there's only one y.

2. The domain are x's, so it's <span> {2, 4, 6, 8}

3. </span>The range are y's, so it's <span> {1, 2, 3, 4}

4.
p=kd\\&#10;7=3k\\&#10;k=\dfrac{7}{3}\\&#10;p=\dfrac{7}{3}d\\&#10;d=\dfrac{3}{7}p\\&#10;d=\dfrac{3}{7}\cdot28=12

5.</span> T(-4)=7-(-4)=7+4=11

6. <span>f(x) = - |x| + 2

7.
C=kt\\&#10;800=4k\\&#10;k=200\\&#10;C=200t
</span>

agasfer [191]3 years ago
6 0
1.\\\#1\ not\ because\ for\ x=-2\to y=2\ and\ y=6\\\#2\ not\ because\ for\ x=1\to y=1\ and\ y=2\\\#3\ \boxed{IT'S\ OK}\leftarrow answer\\\#4\ not\ because\ for\ x=1\to y=2\ and\ y=3\ and...

2.\ (x;\ y)\to x\in D-domain\\\\therefore:\\\\\{(2;1);\ (4;2);\ (6;\ 3);\ (8;\ 4)\}\\\\\boxed{The\ domain\ D=\{2;\ 4;\ 6;\ 8\}}

3.\ (x;\ y)\to y\in Range\\\\\{(2;\ 1);\ (4;\ 2);\ (6;\ 3);\ (8;\ 4)\}\\\\\boxed{the\ range:\{1;\ 2;\ 3;\ 4\}}

4.\\\frac{p}{d}=constans\\\\\frac{28}{d}=\frac{7}{3}\ \ \ \ |cross\ multiply\\\\7\cdot d=3\cdot28\ \ \ \ |divide\ both\ sides\ by\ 7\\\\d=\frac{84}{7}\\\\\boxed{d=12}

5.\ T(z)=7-z\\\\T(-4)\to z=-4\\\\put\ the\ value\ of\ z\ to\ (7-z):\\\\T(-4)=7-(-4)=7+4=\boxed{11}

6.\\y=|x|\to\ the\ axis\ of\ symmetry\ is\ OY\ (S_{OY})\\\\y=-|x|\to\ the\ axis\ of\ symmetry\ is\ OX\ (S_{OX})\\\\so....\ the\ y-intercept\ is\ (0;\ 2),\ therefore\ answer\ is\ \boxed{f(x)=-|x|+2}

7.\\\begin{array}{ccc}C&-&t\\800&-&4\end{array}\ \ \ \ |cross\ multiply\\\\4C=800t\ \ \ \ \ |divide\ both\ sides\ by\ 4\\\\\boxed{C=200t}
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