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Fantom [35]
3 years ago
14

Ex) A nursery plants a new tree and attaches a guy wire to help support the tree

Mathematics
2 answers:
o-na [289]3 years ago
8 0

Answer:

d =   5,35 ft

Step-by-step explanation: See annex

Figure in  annex is clear,  

sin ∠42⁰  = d / 8

And

sin ∠42⁰   =  0.669

d/8   =  0,669

d  =  0,669*8  

d =   5,35 ft

nordsb [41]3 years ago
6 0

Answer:

a ≈ 5.4 ft

Step-by-step explanation:

A guy wire is used to hold a tree firmly to the ground to avoid bending or falling due to earth natural phenomenon like wind.

The guy wire is tied to a stake and attached to the tree. The illustration above forms a right angle triangle. The angle of elevation from the stake in the ground with the tree is 42°.

The tree forms the opposite side of the right angle triangle starting from the point the guy wire was attached down to the base of the tree. The guy wire attached from the tree to the stake forms the hypotenuse of the right angle triangle.

The height of the connection point on the tree is the height of the tree starting from where the guy wire was tied to the tree to the base. Let us call the height a.

hypotenuse = 8 ft

opposite side(a) = ?

angle of elevation = 42°

Using the SOHCAHTOA principle

sin ∅ = opposite/hypotenuse

sin 42° = a/8

cross multiply

a = 8 sin 42°

a = 8 ×  0.6691306064

a =  5.3530448509

a ≈ 5.4 ft

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3/4 of the households in a rural area have pets. how many households have pets in this area if there are 1500 total households
Alex787 [66]

Answer:

1,125 households would have pets in the area.

Step-by-step explanation:

We have 1,500 total households. We also know that 3/4 (or 0.75) of these households have pets. We would multiply 1,500 by 0.75 (which is equal to 3/4), resulting in 1,125. Therefore, 1,125 households would have pets in the area.

8 0
3 years ago
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timofeeve [1]
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3 years ago
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A circle has radius 50 cm. Which of these is closest to its area?
olga55 [171]

Answer:

7854 cm²

Step-by-step explanation:

3.14 x 50² = 7850

4 0
3 years ago
Find the Correlation of the following two variables X: 2, 3, 5, 6 Y: 1, 2, 4, 5
Karolina [17]

Answer:

The correlation of X and Y is 1.006

Step-by-step explanation:

Given

X: 2, 3, 5, 6

Y: 1, 2, 4, 5

n = 4

Required

Determine the correlation of x and y

Start by calculating the mean of x and y

<em>For x</em>

M_x = \frac{\sum x}{n}

M_x = \frac{2 + 3+5+6}{4}

M_x = \frac{16}{4}

M_x = 4

<em>For y</em>

M_y = \frac{\sum y}{n}

M_y = \frac{1+2+4+5}{4}

M_y = \frac{12}{4}

M_y = 3

Next, we determine the standard deviation of both

S = \sqrt{\frac{\sum (x - Mean)^2}{n - 1}}

For x

S_x = \sqrt{\frac{\sum (x_i - Mx)^2}{n -1}}

S_x = \sqrt{\frac{(2-4)^2 + (3-4)^2 + (5-4)^2 + (6-4)^2}{4 - 1}}

S_x = \sqrt{\frac{-2^2 + (-1^2) + 1^2 + 2^2}{3}}

S_x = \sqrt{\frac{4 + 1 + 1 + 4}{3}}

S_x = \sqrt{\frac{10}{3}}

S_x = \sqrt{3.33}

S_x = 1.82

For y

S_y = \sqrt{\frac{\sum (y_i - My)^2}{n - 1}}

S_y = \sqrt{\frac{(1-3)^2 + (2-3)^2 + (4-3)^2 + (5-3)^2}{4 - 1}}

S_y = \sqrt{\frac{-2^2 + (-1^2) + 1^2 + 2^2}{3}}

S_y = \sqrt{\frac{4 + 1 + 1 + 4}{3}}

S_y = \sqrt{\frac{10}{3}}

S_y = \sqrt{3.33}

S_y = 1.82

Find the N pairs as (x-M_x)*(y-M_y)

(2 - 4)(1 - 3) = (-2)(-2) = 4

(3 - 4)(2 - 3) = (-1)(-1) = 1

(5 - 4)(4 - 3) = (1)(1) = 1

(6-4)(5-3) = (2)(2) = 4

Add up these results;

N = 4 + 1 + 1 + 4

N = 10

Next; Evaluate the following

\frac{N}{S_x * S_y} * \frac{1}{n-1}

\frac{10}{1.82* 1.82} * \frac{1}{4-1}

\frac{10}{3.3124} * \frac{1}{3}

\frac{10}{9.9372}

1.006

<em>Hence, The correlation of X and Y is 1.006</em>

4 0
4 years ago
Find the equation of the line with that passes through the
nadya68 [22]

Answer: y = -1

Step-by-step explanation:

Use the slope formula and slope-intercept form y=mx+b to find the equation

3 0
3 years ago
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