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3 years ago

14

Ex) A nursery plants a new tree and attaches a guy wire to help support the tree

2 answers:

o-na [289]3 years ago

8 0

Answer:

d = 5,35 ft

Step-by-step explanation: See annex

Figure in annex is clear,

sin ∠42⁰ = d / 8

And

sin ∠42⁰ = 0.669

d/8 = 0,669

d = 0,669*8

d = 5,35 ft

nordsb [41]3 years ago

6 0

Answer:

a ≈ 5.4 ft

Step-by-step explanation:

A guy wire is used to hold a tree firmly to the ground to avoid bending or falling due to earth natural phenomenon like wind.

The guy wire is tied to a stake and attached to the tree. The illustration above forms a right angle triangle. The angle of elevation from the stake in the ground with the tree is 42°.

The tree forms the opposite side of the right angle triangle starting from the point the guy wire was attached down to the base of the tree. The guy wire attached from the tree to the stake forms the hypotenuse of the right angle triangle.

The height of the connection point on the tree is the height of the tree starting from where the guy wire was tied to the tree to the base. Let us call the height a.

hypotenuse = 8 ft

opposite side(a) = ?

angle of elevation = 42°

Using the SOHCAHTOA principle

sin ∅ = opposite/hypotenuse

sin 42° = a/8

cross multiply

a = 8 sin 42°

a = 8 × 0.6691306064

a = 5.3530448509

a ≈ 5.4 ft

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3 years ago

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Reptile [31]

we are given

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We can see that

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now, we will check each terms

At x=-2:

We can use synthetic division

we get

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and we can write our expression from synthetic division as

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now, we can find factor of remaining terms

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we can use quadratic formula

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we can compare our equation with quadratic equation

we get

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$x=-1+\sqrt{2}i,\:x=-1-\sqrt{2}i$

so, we can write factor as

$x^2+2x+3=(x-(-1+\sqrt{2}i))(x-(-1-\sqrt{2}i))$

so, we get completely factored form as

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