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Tema [17]
3 years ago
10

Which equation has roots of -1 and 2?

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
4 0

Answer:

(x+1) (x-2) = 0

Step-by-step explanation:

Roots = -1 and 2

This means

X = -1 or x = 2

(x + 1) = 0 or (x -2) = 0

Combine the two equations

(x+1) (x-2) = 0

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A city water company charges homeowners based on how much water they use in thousands of gallons. The company progressively char
Dima020 [189]

Answer:

  • 1700: $50
  • 2000: $60
  • 7000: $90

Step-by-step explanation:

You can read the answers from the graph. Find the usage on the horizontal scale, and look at the vertical scale to find the corresponding charge.

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<h3>1700 gallons</h3>

The value 1700 is between 1000 and 2000, so will be between 1 and 2 on the horizontal scale. The graph is flat in that region. The charge is $50.

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<h3>2000 gallons</h3>

The graph has a jump at 2 on the horizontal scale. The solid dot tells you that the charge is $60.

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<h3>7000 gallons</h3>

At 7 on the horizontal scale, the graph is increasing from 80 to 100. At 7000 gallons, the line passes through the grid intersection indicating the charge is $90.

4 0
2 years ago
A carton of one dozen eggs costs $1.92. What is the unit price of each egg?
telo118 [61]

Answer:

$0.16

Step-by-step explanation:

unit price = price of carton / number of eggs

unit price = $1.92/12

unit price = $0.16

5 0
2 years ago
Solve the inequality<br>w/2&lt;-42​
exis [7]

Answer:

w<-84

Step-by-step explanation:

solved the equation

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3 years ago
One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p
scZoUnD [109]

Answer:

c^2 = 9dp

Step-by-step explanation:

Given

dx^2 + cx + p = 0

Let the roots be \alpha and \beta

So:

\alpha = 2\beta

Required

Determine the relationship between d, c and p

dx^2 + cx + p = 0

Divide through by d

\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0

x^2 + \frac{c}{d}x + \frac{p}{d} = 0

A quadratic equation has the form:

x^2 - (\alpha + \beta)x + \alpha \beta = 0

So:

x^2 - (2\beta+ \beta)x + \beta*\beta = 0

x^2 - (3\beta)x + \beta^2 = 0

So, we have:

\frac{c}{d} = -3\beta -- (1)

and

\frac{p}{d} = \beta^2 -- (2)

Make \beta the subject in (1)

\frac{c}{d} = -3\beta

\beta = -\frac{c}{3d}

Substitute \beta = -\frac{c}{3d} in (2)

\frac{p}{d} = (-\frac{c}{3d})^2

\frac{p}{d} = \frac{c^2}{9d^2}

Multiply both sides by d

d * \frac{p}{d} = \frac{c^2}{9d^2}*d

p = \frac{c^2}{9d}

Cross Multiply

9dp = c^2

or

c^2 = 9dp

Hence, the relationship between d, c and p is: c^2 = 9dp

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3 years ago
A dilation is a transformation whose preimage and image are
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A different size but not does not change shape.
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