The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Given that,
- The ground temperature at the airport is 10 °C.
- The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.
Based on the above information, the temperature outside should be
The decrease in the temperature should be
= 5.4×5
= 27°C
Now the final temperature is
= 10 - 27
= -17°C
Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Learn more: brainly.com/question/20459283
3/4x - 16 = 28
+16 +16
3/4x = 44
*3/4 *3/4
x = 176/3
Answer:
Step-by-step explanation:
85 degrees. Step-by-step explanation: From the diagram, it is clearly visible that the angle ∠ABC is formed by intersections of two chords AE and CD of the circle.
5 miles high is one of the sides of a triangle depending on accuracy level
h^2=x^2+y^2
we don't have 2 distances
Tan A=O/a
O=a tan A
We solve for O because the angle is at the top of the line going up and we want the opposite angle that is along the ground
O=5×tan(173.7/2)=90.854033512
The distance he can see is:
90.85*2~181.7 miles
Now we need to find the distance between lines:
The north south distance between each line is 69 miles
thus the number of degrees he will see will be:
181.7/69
=2 19/30
Answer:
Size of each group = 
Step-by-step explanation:
Total number of paint brushes = x
Since each the three groups are equally sized, to get the number of paintbrushes in a group, we will have to divide the total number of paint brushes by 3
∴ We have, number of paint brushes in a group = 
=
this is also the same thing as saying 
×
This shows that the size of the new group is the same as the size of the original group
