All categories

2 years ago

In the diagram, CA is tangent to circle P. The e

Mathematics

2 answers:

Alecsey [184]2 years ago

6 0

Answer:

C. 15 cm

Explanation:

The radius is the same in a circle. PA and PB has same length of 8 cm.

In order to find AC, find the length of PA and PC.

Here given:

PA = 8 cm

PC = PB + BC = 8 cm + 9 cm = 17 cm

Hence solve using Pythagoras theorem:

a² + b² = c²

AC² + PA² = PC²

AC² + 8² = 17²

AC² = 289 - 64

AC = √225

AC = 15

satela [25.4K]2 years ago

4 0

Radius hits any tangent at 90°

AC²=PC²-AP²
AC²=(9+8)²-8²
AC²=17²-8²
AC²=289-64
AC²=225
AC=15cm

You might be interested in

Write 7x^2 -4 + 6x^3 -4x -x^4 in standard form

Nata [24]

-x⁴+ 6x³- 7x²- 4x - 4

Order from least to greatest exponent (the variable, which is x in this case, is always first by the way in terms of order, then integers). This point of this problem is essentially to just rearrange the original equation.

3 0

2 years ago

I am not sure how to figure this out.

umka2103 [35]

Change them all into the same unit of measurement and you will see which is the furthest out by default.

3 0

4 years ago

I need help on this one <br>(IF YOU HELP ME THANKSSS SO MUCH ❤)

ryzh [129]

The answer to this question is b

4 0

3 years ago

Read 2 more answers

A package is dropped from a helicopter that is moving upward at 20.0 m/s. If it takes 18.0s before the package strikes the groun

tekilochka [14]

Answer:

We have for velocity of package v= 20 - 9.8t and for distance from the ground y = h + 20t - 4.9t2.

We have y = 0 and t = 18.0 s we have h = 4.9·182 - 20·18 = 1227.6 m.

Velocity at landing v = 20 - 9.8·18 = - 156.4 m/s

6 0

4 years ago

In a grid of a backyard, the vertices of the floor of a shed are (20, 80), (50, 60), (50, 20), and (20, 20). The coordinates are

sdas [7]

Answer:

The area of the floor of the shed is <u>1500 square feet.</u>

Step-by-step explanation:

Given:

The vertices of the floor of a shed are: (20,80), (50,60), (50,20) and (20,20)

Let us plot the given vertices on a graph.

From the graph, it is clear that the given figure is a trapezium with opposite parallel sides being parallel to the y axis. The height of the trapezium is the side that is parallel to x axis.

The area of the trapezium ABCD is given as:

$A=\frac{1}{2}(AB+CD)\times AD$

From the graph, AB = 60 ft, CD = 40 ft, AD = 30 ft

Therefore, the area is given as:

$A=\frac{1}{2}(60+40)\times 30\\A=\frac{1}{2}\times 100\times 30=1500\ ft^2$

Therefore, the area of the floor of the shed is 1500 square feet.

4 0

4 years ago