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2 years ago

The following a function (6,3), (-1,2), (-1,-1), (4,3)

Mathematics

1 answer:

Akimi4 [234]2 years ago

5 0

for an expression or relation to be a function, it must not have any x-coordinate values repeated, let's check this one

$\bf (6,3), (\stackrel{\stackrel{rep eated}{\downarrow }}{-1},2), (\stackrel{\stackrel{rep eated}{\downarrow }}{-1},-1), (4,3)\qquad \textit{not a function}$

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Which factorization is equivalent to this expression<br> -32xy + 20y - 14

densk [106]

Answer:

-2(16xy-10y+7)

Step-by-step explanation:

-2(16xy-10y-7)= -2×16xy-2(-10y)-2×7

-2(16xy-10y+7)= -32xy+20y-14

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2 years ago

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Answer:04

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3 years ago

Graph the circle x2 + y2 + 10x + 6y + 18 = 0.

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Answer:

see below for a graph

Step-by-step explanation:

Completing the square for x and y terms can help you put this in the standard form.

(x^2 +10x) +(y^2 +6y) = -18

(x^2 +10x +25) +(y^2 +6x +9) = -18 +25 +9 . . . . add square of half linear coefficient

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3 years ago

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6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the

MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

$a_1$ the horizontal distance between the first observer and the ballonist

$a_2$ the horizontal distance between the second observer and the ballonist

$\alpha _1$ and $\alpha _2$ the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

$S=a*h$ (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

$S=S_1+S_2$ (equation 2)

$S_1=a_1*h$

But we can write $S_1$ in terms of $\alpha _1$ , like this:

$\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}$

And for $S_2$ will be the same:

$S_2=\frac{h^{2} }{\tan(\alpha _2)}$

Replacing in the equation 2:

$S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})$

And replacing in the equation 1:

$h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}$

So, we can replace all the known data in the last equation:

$h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft$

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

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2 years ago

Mr. Curry puts $5,500 in an investment account that offers 8% interest compounded annually. He makes no additional deposits or w

aalyn [17]

Answer:

B.$12,100.00

Step-by-step explanation:

it is a pleasure to help you hope you understand if you have a question you can ask me or send me a help request.good luck.

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2 years ago