Simplify the following expression and write in standard form: 3 x (6y - 4y + 5x) PLEASE HELP

Mathematics

1 answer:

mylen [45]4 years ago

8 0

Answer: 15x^2+6xy

Step-by-step explanation: 3x(6y−4y+5x)

(3x)(6y+−4y+5x)

(3x)(6y)+(3x)(−4y)+(3x)(5x)

18xy−12xy+15x^2

15x^2+6xy

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irina1246 [14]

Answer:

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Step-by-step explanation:

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3 years ago

Need help with #1 Thank you.

lbvjy [14]

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4 years ago

At time t hours after taking the cough suppressant hydrocodone bitartrate, the amount, A, in mg, remaining in the body is given

Nostrana [21]

Answer:

a. The initial amount was 10 mg.

b. The percentage of the drug leaving the body each hour is 0.18, this is 18% per hour.

c. The amount of drug that remains in the body 6 hours after dosing is 3.04 mg.

d. The time until only 1 mg of the drug remains in the body is 11.6 hours.

Step-by-step explanation:

You know that at time t hours after taking the cough suppressant hydrocodone bitartrate, the amount, A, in mg, remaining in the body is given by :

$A=10*(0.82)^{t}$

a. The initial quantity occurs when time t is the initial t, that is, t is equal to 0. Then:

$A=10*(0.82)^{t}=10*(0.82)^{0}=10*1\\$

A=10

The initial amount was 10 mg.

b. Considering that an exponential growth is determined by:

$A=A0*(1-r)^{t}$ , where A is the amount after a certain number of a certain time, Ao is the initial amount, r is the rate and t is the time, so the percentage of the drug that leaves the body each hour is :