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Ira Lisetskai [31]
3 years ago
14

Simplify the following expression and write in standard form: 3 x (6y - 4y + 5x) PLEASE HELP

Mathematics
1 answer:
mylen [45]3 years ago
8 0

Answer: 15x^2+6xy

Step-by-step explanation: 3x(6y−4y+5x)

(3x)(6y+−4y+5x)

(3x)(6y)+(3x)(−4y)+(3x)(5x)

18xy−12xy+15x^2

15x^2+6xy

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lys-0071 [83]

Answer:

a) 21/1240 = 0.017

b) 9/1240 = 7.26*10^-3

c) 3/2480 = 1.21*10^-3

Step-by-step explanation:

There are total 32 M&Ms in the bag

a) Probability that all three are blue M&Ms (without replacement)

         (9/32)*(8*31)*(7/30) = 21/1240 = 0.017

b)     Probability that the first one selected is blue, the second one selected is orange, and the third one selected is red

         (9/32)*(6/31)*(4/30) = 9/1240 = 7.26*10^-3

c)     Probability that the first two selected are red, and the third one selected is yellow

        (4/32)*(3/31)*(3/30) = 3/2480 = 1.21*10^-3

3 0
3 years ago
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3 years ago
Exponetial funtion is
r-ruslan [8.4K]

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4 0
3 years ago
Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (
natulia [17]

Answer:

I= 84

Step-by-step explanation:

for

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{}_{} \int\limits^{}_D {x*y}  \, dx*dy

since D is the rectangle such that 0<x<3 , 0<y<3

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y}  \, dx*dy =  \int\limits^{3}_{0} {x}  \, dx\int\limits^{3}_{0} {y}  \, dy  = x^{2} /2*y^{2} /2 =  (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4

4 0
3 years ago
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