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3 years ago

10

The circle below is centered at (10,4) and has a radius of 4. What it’s equation?

1 answer:

Rina8888 [55]3 years ago

5 0

Answer:

$(x-10)^2 + (y-4)^2 = 16$

Step-by-step explanation:

To write the equation using a center and a radius, use the vertex form of the equation.

$(x-h)^2+(y-k)^2 = r^2$

Substitute the values h=10 and k=4 into the equation along with r = 4.

$(x-10)^2 + (y-4)^2 + 4^2\\(x-10)^2 + (y-4)^2 = 16$

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Read 2 more answers

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Answer:

Prism A:

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Prism B:

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Step-by-step explanation:

Given

See attachment for prisms

$Height(h) = 10cm$

Required

Determine the surface area of both prisms

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$Area = 2 * A_b + (a + b + c) * h$

Where

$A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}$

and

$s = \frac{a + b + c}{2}$

Such that a, b and c are the lengths of the triangular sides of the prism.

From the attachment;

$a = 8; b =6; c =10$

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$s = \frac{a + b + c}{2}$

$s = \frac{8 + 6 + 10}{2}$

$s = \frac{24}{2}$

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Also:

$A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}$

$A_b = \sqrt{12 * (12 - 8) * (12 - 6) * (12 - 10)}$

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