Kirsten's work is shown below:

Help me guys.... running out of points here this is a test grade....gonna die

Murrr4er [49]

Answer:

11

Step-by-step explanation:

The sum of the remote interior angles = the exterior angle

66 + 7x + 7 = 12x + 18

7x + 73 = 12x + 18

55 = 5x

x = 11

5 0

3 years ago

Lana sells lampshades for $8 each and paper lanterns for $5 each at a one-day craft fair. She sells k lampshades and (k+5) paper

DENIUS [597]

Answer:

8k + 5k + 25

Or

13k + 25

Step-by-step explanation:

Lana's total sales = 8k + 5(k+5)

Since the expressions are not given in the question;

The equivalent expression could be

= 8k + 5k + 25

Equivalent to

= 13k + 25

3 0

3 years ago

3

Furkat [3]

Answer:

There are as many definitions of empire as there have been empires, but some pretty familiar elements appear in most of them. It starts with working on our “control issues”.

3 0

2 years ago

F(x) =5+ 1 , find f(-4)

tester [92]

Answer:

Step-by-step explanation:

F(x) =5x + 1 , find f(-4)

Putting value of x = 4

F(4) = 5(4) + 1

= 20 + 1 = 21

5 0

3 years ago

⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden

fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = $\frac{354}{1219}$

n = sample of US adults = 1291

p = population proportion of adults

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

significance level are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

<u>95% confidence interval for p</u> = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]

= [ $\frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ , $\frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ ]

= [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0

3 years ago