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2 years ago

3

Mathematics

1 answer:

Furkat [3]2 years ago

3 0

Answer:

There are as many definitions of empire as there have been empires, but some pretty familiar elements appear in most of them. It starts with working on our “control issues”.

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Please help me with this it's my last question on my homework :)

Levart [38]

The answer your looking for is 60ft

5 0

3 years ago

Read 2 more answers

You have a goal of saving to build up a nest egg of $625,357.24, and you are going to make regular deposits to an account that p

Delvig [45]

The monthly deposit required to save up to $625,357.24 (future value) in 40 years at a 7.2% APR is $225.20.

<h3>What is the monthly deposit?</h3>

The monthly deposits are the periodic savings that the investor must make to achieve future value.

The monthly deposit is compounded at the monthly annual percentage rate (APR).

We can compute the required monthly deposits using an online finance calculator as follows:

N (# of periods) = 480 months (40 years x 12)

I/Y (Interest per year) = 7.2%

PV (Present Value) = $0

FV (Future Value) = $625,357.24

Results:

Monthly Deposits (PMT) = $225.20

Sum of all periodic payments = $108,096 ($225.20 x 480)

Total Interest = $517,261.24

Thus, to save $625,357.24 in 40 years, you need to deposit $225.20 monthly.

Learn more about periodic deposits (payments) at brainly.com/question/13031679

#SPJ1

6 0

1 year ago

Pls help ratios and proportions

kifflom [539]

Answer: See explanation

Step-by-step explanation:

3.) Boys║5║10 ║60

Girls ║7║ 14 ║84

7 × 2 = 14

5 × 2 = 10

5 × 12 = 60

7 × 12 = 84

Hope I helped!

5 0

3 years ago

The length of a rectangle is three inches more than the width. the area of the rectangle is 180 inches. find the width of the re

ch4aika [34]

We have a rectangle with length L that is 3 inches more than the width W. Then we can write this as:

$L=W+3$

The area of the rectangle is 180 square inches.

We have to find the width W.

As the area is equal to the product of the length and the width, we can write this equation and solve for W as:

$\begin{gathered} A=180 \\ L\cdot W=180 \\ (W+3)\cdot W=180 \\ W^2+3W=180 \\ W^2+3W-180=0 \end{gathered}$

We have a quadratic equation. The roots of this equation will be the mathematical solutions.

We can find the roots using the quadratic formula:

$\begin{gathered} W=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ W=\frac{-3\pm\sqrt[]{3^2-4\cdot1\cdot(-180)}}{2\cdot1} \\ W=\frac{-3\pm\sqrt[]{9+720}}{2} \\ W=\frac{-3\pm\sqrt[]{729}}{2} \\ W=\frac{-3\pm27}{2} \\ W_1=\frac{-3-27}{2}=-\frac{30}{2}=-15 \\ W_2=\frac{-3+27}{2}=\frac{24}{2}=12 \end{gathered}$

The solutions are W = -15 and W = 12.

The first one is not valid, as W has to be greater than 0.

Then, the solution to our problem is W = 12 in.

Answer: the width is W = 12 inches.

6 0

1 year ago

Suppose that a die-hardly-ever battery has an exponential time-to-failure distribution with a mean of 48 months. at 60 months, t

mel-nik [20]

Since the time to failure distribution is exponential, the distribution is F (n) = 1 – e ^ (-x/48)

The probability of failure between months 60 and 72 is the same as the probability that the battery will fail in 12 months, since the exponential distribution is memoryless F (12) = 0.221

7 0

3 years ago