The diameter is 46 and the radius is 11.5
Answer:
The range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].
Step-by-step explanation:
We are given that the lengths of pregnancies in a small rural village are normally distributed with a mean of 262 days and a standard deviation of 17 days.
Let X = <u><em>lengths of pregnancies in a small rural village</em></u>
SO, X ~ Normal(
)
Here,
= population mean = 262 days
= standard deviation = 17 days
<u>Now, the 68-95-99.7 rule states that;</u>
- 68% of the data values lies within one standard deviation points.
- 95% of the data values lies within two standard deviation points.
- 99.7% of the data values lies within three standard deviation points.
So, middle 68% of most pregnancies is represented through the range of within one standard deviation points, that is;
[
,
] = [262 - 17 , 262 + 17]
= [245 days , 279 days]
Hence, the range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].
Step 1 should be
Bring the constant to the other side and divide the whole equation with 6 resulting to
x2 + 4x = -7/6
Step 3 should be
Complete the square by dividing the coefficient of x by 2, squaring it and adding the result to both sides of the equation.
x2 + 4x + 4 = -7/6 + 4
Step 4 should be
Factor the quadratic equation and simplify
(x+2)2 = -17/6
Step should be
Get the square root of booth sides and solve for the values of x
x+2 = +-√(102) / 6
So,
x = -2 + √(102) / 6 and x = -2 - <span>√(102) /3
</span>
Answer:
$5.95
Step-by-step explanation:
To get the discounted price, we need to find how much is taken off from the regular price.
x/8.50=30/100
30×8.50=255
255/100=2.55
$2.55
Next, we need to subtract $2.55 from $8.50 to get the discounted price.
8.50-2.55=5.95
$5.95
$5.95 is the discounted price.
<em><u>I</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helped</u></em><em><u>!</u></em><em><u> </u></em><em><u>:</u></em><em><u>)</u></em>
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(x+11)(x−1)
(x+11)(x+1)
(x−11)(x+1)
(x−11)(x−1)