Please help me answer this :)?

Fred has 32 ounces of cookie dough. If he used 0.56 ounces of cookie dough for each cookie, what is a reasonable estimate of how

8_murik_8 [283]

Answer:

57 cookies

Step-by-step explanation:

32/0.56= 57.14

4 0

2 years ago

since the 1950's, air pollution and robberies have increased. the conclusion that air pollution causes robberies is

dlinn [17]

Had to look for the options and here is my answer.
Starting from the 1950s, both robberies and air pollution has increased and the conclusion that we can say regarding this increase is NOT JUSTIFIABLE. It is not justifiable because population is a different variable and they are not directly related to each other. Hope this helps.

8 0

3 years ago

Read 2 more answers

What is the area of the yellow square?The area of the green square is 9 ft2. The area of the red square is 16 ft2.

joja [24]

Well abnormal square would have four equal sides therefore for the firemen square since it's 9 ft^2 then u square root it and u get 3 that means each side in that green square is 3 now for the red one with 16ft^2 it would be the same consept u would square root 16 which u would get 4 now the two legs are 3 and four now u are missing the hypotenuse at c thus u use pythogerom theorom I don't know how to spell it so don't complain! You would do 3^2+4^2=c^2 which would result to 9+16=c^2. From there u would add and you would get 25 =c^2 and the reverse property of square would be square root it's that radical symbol if u remember so radical 25=5. We are still not finished we have to find the area and since we are working with normal squares where each sides ar eewual then u do 5*5 u get 25!
Now don't forget to write ft2 because then u will get it wrong
And don't be a lazy bum and try rechecking my work because I did it all in my head ok it's 12 o'clock a.m.
Peace

7 0

3 years ago

Read 2 more answers

The United States Coast Guard assumes the mean weight of passengers in commercial boats is 185 pounds. The previous value was lo

Valentin [98]

Answer:

There is a 5.5% probability that a random sample of passengers will have a mean weight that is as extreme or more extreme (either above or below the mean) than was observed in this sample.

Step-by-step explanation:

To solve this problem, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

In this problem, we have that:

$\mu = 185, \sigma = 26.7, n = 48, s = \frac{26.7}{\sqrt{48}} = 3.85$

The weights of a random sample of 48 commercial boat passengers were recorded. The sample mean was determined to be 177.6 pounds. Find the probability that a random sample of passengers will have a mean weight that is as extreme or more extreme (either above or below the mean) than was observed in this sample.

The probability of an extreme value below the mean.

This is the pvalue of Z when X = 177.6.

So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{177.6 - 185}{3.85}$

$Z = -1.92$

$Z = -1.92$ has a pvalue of 0.0274.

So there is a 2.74% of having a sample mean as extreme than that and lower than the mean.

The probability of an extrema value above the mean.

Measures above the mean have a positive z score.

So this probability is 1 subtracted by the pvalue of $Z = 1.92$

$Z = 1.92$ has a pvalue of 0.9726.

So there is a 1-0.9726 = 0.0274 = 2.74% of having a sample mean as extreme than that and above than the mean.

Total:

2*0.0274 = 0.0548 = 0.055

There is a 5.5% probability that a random sample of passengers will have a mean weight that is as extreme or more extreme (either above or below the mean) than was observed in this sample.

4 0

3 years ago

What values of b will cause 4x^2+bx+25=0 to have one real solution?

Darina [25.2K]

Answer:

b=20 or b=-20

Step-by-step explanation:

Keep in mind the meanings of the values of the discriminant:

If b^2-4ac=0, then the quadratic will have only 1 solution (double root)

If b^2-4ac<0, then the quadratic will have no real solutions

If b^2-4ac>0, then the quadratic will have 2 unique solutions

In this case, to get one real solution, the discriminant must be set up as b^2-4ac=0. Setting up the equation we get:

b^2-4(4)(25)=0

b^2-400=0

b^2=400

b=20 or b=-20

So the values of b would have to be either 20 or -20

5 0

3 years ago