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Elza [17]
3 years ago
6

What is the scale factor of the dilation?

Mathematics
2 answers:
LenaWriter [7]3 years ago
5 0

Answer:

1/3

Step-by-step explanation:

To find the scale factor write a ratio from the side length of the small triangle to a corresponding side length of the large triangle.

C'B' has the distance 3 units and CB has the distance 9 units.

The ratio then is 3/9 = 1/3. So the scale factor is 1/3 because it is shrinking the larger triangle to the smaller as shown by the ' marks on the letters.

vovikov84 [41]3 years ago
3 0

Answer: C. \dfrac{1}{3}

Step-by-step explanation:

The coordinates of vertices of any figure(pre-image) (x,y) after dilation with scale factor 'k' will become : (kx,ky)→ Image.

such that k=\dfrac{\text{coordinate of x in image}}{\text{coordinate of x in pre-image}}

From the given figure, the coordinates of point C (in pre-image)=(-6,-6)

And the coordinates of image = (-2,-2)

\\\\\Rightarrow\ k=\dfrac{-2}{-6}=\dfrac{1}{3}

Hence, the scale factor of the dilation  = \dfrac{1}{3}

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marysya [2.9K]

Answer:

2. $2.31

Step-by-step explanation:

25% off, 75% to be paid

75/100 × 31.5 = 23.625

20% off, 80% to be paid

80/100 × 26.75 = 21.4

18% off, 82% to be paid

82/100 × 26 = 21.32

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23.625 - 21.32

2.305

7 0
3 years ago
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Which of the following is not equal to sin⁡(-230°)?
xenn [34]

From trigonometry we know that:

if sin(\theta)=sin(\alpha)

then, \theta=n\pi+(-1)^n\alpha (where n is an integer)

This can be rewritten in degrees as:

\theta=n(180^{\circ})+(-1)^n\alpha.............(Equation 1)

Now, in our case, \alpha=-230^{\circ}

Therefore, (Equation 1) can be written as:

\theta=n(180^{\circ})+(-1)^n(-230^{\circ})..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of \theta that match.

For n=2, (Equation 2) gives us: \theta=2\times 180^{\circ}+(-1)^2(-230^{\circ})=360^{\circ}-230^{\circ}=130^{\circ}.

Thus, sin(230^{\circ})=sin(130^{\circ})

Now, we know that: -sin(-50^{\circ})=sin(50^{\circ})

Let n=-1, then:

\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}

Thus, sin(-230^{\circ})=-sin(-50^{\circ})

Likewise, sin(-230^{\circ})=sin(50^{\circ})

Only the last option sin(-50^{\circ}) will never match sin(-230^{\circ}) because no integral value of n will ever give \theta=-50^{\circ}

Thus the last option is the correct option.

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3 years ago
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Factor this expression completely.<br> 36y2 - 1
shtirl [24]

Answer:

(6y - 1)(6y + 1)

Step-by-step explanation:

To factorize completely, we may adopt the difference of 2 squares approach. The theory states that difference of two square  is the product of the difference of the number and the sum of the numbers.

Such that

a² - b² = (a - b) (a + b)

Hence 36y² - 1

= 6²y² - 1²

= (6y)² - 1²

= (6y - 1)(6y + 1)

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4 years ago
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The two pictures are the questions and question five is what i need help with.
Mama L [17]

Answer:yes they do

Step-by-step explanation:

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3 years ago
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I'LL GIVE YOU BRAINIEST!<br> 1 1/5 · x/3 = 9/10 solve for x
joja [24]

\huge\text{Hey there!}

\huge\textbf{Equation:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\huge\textbf{Solve:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{1\times5+1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{5 + 1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{6}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\huge\textbf{Simplify it:}

\mathbf{\rightarrow \dfrac{2}{5}x = \dfrac{9}{10}}

\huge\textbf{Multiply \boxed{\bf \dfrac{5}{2}} to both sides:}

\mathbf{\rightarrow \dfrac{5}{2}\times \dfrac{2}{5}x = \dfrac{5}{2}\times \dfrac{9}{10}}

\huge\textbf{Simplify it:}

\mathbf{\rightarrow x = \dfrac{5}{2}\times \dfrac{9}{10}}

\mathbf{\rightarrow x = \dfrac{5\times9}{2\times10}}

\mathbf{\rightarrow x = \dfrac{45}{20}}

\mathbf{\rightarrow x = \dfrac{45\div5}{20\div5}}

\mathbf{\rightarrow x = \dfrac{9}{4}}

\mathbf{x \approx 2 \dfrac{1}{4}}

\huge\textbf{Therefore, your answer should be:}

\huge\boxed{\mathsf{x = }\frak{2 \dfrac{1}{4}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

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