For the linear equation above, y=1/2x-5, is the point (-14,-13) on this line? Explain how you know.
1 answer:
You might be interested in
<h3>The Graph you need above </h3><h3>Step-by-step explaination : </h3><h3>Combine 1/3and x.</h3>
y<x/3+1/2
<h3>Use the slope-intercept form to find the slope and y-intercept.</h3><h3 />Slope: 1/3
y-intercept: 1/2
<h3>Graph a dashed line, then shade the area below the boundary line since y is less</h3><h3>than x/3+1/2.</h3><h3>y<x/3+1/2</h3>
Answer:
To perpendicular bisector of line segment WX. There are following steps:
1) Draw arcs or circles from points A and B on the both sides of WX.
2) Name the intersection points as W and X.
3) Use the straightedge to draw a line through points W and X.
4) Name the point as O
hence we have construct perpendicular bisector AB of WX which bisects at O.
