Ask question

Ask question

All categories

4 years ago

5

Find the distance between the points (10,1) and (5,4)

1 answer:

Amanda [17]4 years ago

6 0

Answer:

Step-by-step explanation:

distance formula = $\sqrt{(y_2-y_1)^{2}+(x_2-x_1)^2 }$

Plug in the points and you get = 5.83

You might be interested in

Hi please help , With solution if it's ok

Snowcat [4.5K]

<u>Answers </u><u>with </u><u>Method</u><u>:-</u>

1) Multiply the length value by 100,000.

$2.5 \: hm = 2.5 \times 100000$

$= >2.5 \: hm = 250000 \: mm$

2) For this, divide the length value by 1000.

$= > \frac{1800}{1000}$

$= > 1.8 \: dam$

3) For finding the approximate value, just multiply the value of length by 1.609.

$= >6450 \: m = (6450 \times 1.609) \: km$

$= > 10380.27 \: km$

4) Multiply the given mass value by 100.

$= > 1.2 \: kg = 1.2 \times 100$

$= > 1200 \: g$

5) Multiply the given value by 10,000.

$4.37 \: dag = 4.37 \times 10000$

$= > 43700 \: mg$

5 0

2 years ago

Simplify the exponential expression <br> A- 5cdf<br> B- 60cdf<br> C- 60cdf <br> D- 5cdf

jekas [21]

------------------------------
(75c^2d^4f^8)/(15cd^3f^4)

75/15 x c^2d^4f^8 over cd^3f^4

5 x c^2d^4f^8 over cd^3f^4

5c^2-1d^4-3f^8-4

5c^1d^4-3f^8-4

5c^1d^1f^8-4

5c^1d^1f^4

5cd^1f^4

5cdf^4 or option A.
------------------------------

5 0

3 years ago

iVinArrow [24]

Given:

The data set is

10, 10, 11, 12, 13, 13, 13, 14, 14, 15, 15, 15, 16, 17, 17, 17, 35

To find:

Effect on mean, median, range after removing the outlier, 35.

Solution:

We have, the data set

10, 10, 11, 12, 13, 13, 13, 14, 14, 15, 15, 15, 16, 17, 17, 17, 35

$\text{Mean}=\dfrac{\text{Sum of observations}}{\text{Number of observations}}$

$\text{Mean}=\dfrac{10+10+11+12+13+13+13+14+14+15+15+15+16+17+17+17+35}{17}$

$\text{Mean}=\dfrac{257}{17}$

$\text{Mean}=15.117647$

$\text{Mean}\approx 15.12$

Mean of the data set is 15.12.

$Median=\dfrac{n+1}{2}\text{th term}$ because n=17, which is odd.

$Median=\dfrac{17+1}{2}\text{th term}$

$Median=\dfrac{18}{2}\text{th term}$

$Median=9\text{th term}$

$Median=14$

Median is 14.

$Range=Maximum-Minimum$

$Range=35-10$

$Range=25$

Range is 25.

After removing the outlier, 35, the data set is

10, 10, 11, 12, 13, 13, 13, 14, 14, 15, 15, 15, 16, 17, 17, 17

$\text{Mean}=\dfrac{10+10+11+12+13+13+13+14+14+15+15+15+16+17+17+17}{16}$

$\text{Mean}=\dfrac{222}{16}$

$\text{Mean}=13.875$

Mean of the new data set is 13.875, which is less than 15.12.

$Median=\dfrac{\dfrac{n}{2}\text{th term}+(\dfrac{n}{2}+1)\text{th term}}{2}$ because n=16, which is even.

$Median=\dfrac{\dfrac{16}{2}\text{th term}+(\dfrac{16}{2}+1)\text{th term}}{2}$

$Median=\dfrac{8\text{th term}+9\text{th term}}{2}$

$Median=\dfrac{14+14}{2}$

$Median=\dfrac{28}{2}$

$Median=14$

New median is 14, which is same as original median.

$Range=17-10$

$Range=7$

So, the new range is 7 which is less than 25.

Therefore, the mean of the data set will decrease, the median of the data set will not change, the Range of the data set will decrease.

5 0

3 years ago

Read 2 more answers

Vikki [24]

If the function is f(x) = 6(0.4)x then the domain is ALL REAL NUMBERS and the range is ALL REAL NUMBERS!

3 0

3 years ago

The _____ of a line is y=mx+b. The variable m in the equation stands for the _____. The variable b in the equation stands for th

baherus [9]

Answer:

The answers in order are:

slope-intercept form

slope of a line

y-intercept

Step-by-step explanation:

These are the definitions of the terms.

y=mx+b is called slope-intercept form because it contains the slope (m) and y-intercept (b)

slope of a line is change in y over change in x (steepness) which is m

y-intercept is point line intercepts y-axis and is b

6 0

3 years ago