Answer: B (x=1)
The x-axis shows all the zeros (solutions).
If you were trying to find the slope and the equation of the line, you would go y/x for the slope.
While, b is the y axis, which is 3 in this case.
And the slope is 3/1, which is rise over run (y/x)
Linear equations: y = mx+b
Quadratic equation: ax^{2}+bx+c
(Not going to go in much more depth)
The equation of this line is y = 3x + 1
Answer: C
Step-by-step explanation:
A function has to have a pattern, and should be able to be written as a function. C is the only one with a pattern that doesn't suddenly change in between.
Answer:
The standard form of an equation of the line that passes through the given point having slope is 
Step-by-step explanation:
The standard form of an equation of the line that passes through the given point (
and having slope m is
another form of an equation of the line that passes through the given point (
and having slope m is
y=m x
9514 1404 393
Answer:
55,637.8 square inches
Step-by-step explanation:
We can find side n using the Law of Sines:
n/sin(N) = p/sin(P)
n = p(sin(N)/sin(P)) = 600·sin(64°)/sin(96°)
n ≈ 542.246913 . . . . inches
The angle O is ...
O = 180° -N -P = 180° -64° -96° = 20°
Then the area is ...
A = 1/2·np·sin(O)
A = (1/2)(542.246913 in)(600 in)·sin(20°) ≈ 55,637.81008 in²
The area of ∆NOP is about 55,637.8 in².
Answer:
5 trips
Step-by-step explanation:
Note that the weight and volume of the load must not exceed the given maximum.
Volume of load = 19.8m^3
Density of load = 650kg/m^3
Mass of load = 19.8 × 650 = 12,870 kg
Given limits.
Volume = 4m^3
Mass = 3700kg
Assuming the truck is to carry 4m^3 of the load.
The mass of 4m^3 of the load is = 4 × 650 = 2600kg
Mass = 2600kg < 3700kg
Therefore it satisfies both conditions.
The number of trip the truck would make is;
N = total volume of load/ volume per trip
N = 19.8/4
N = 4.95
N = 5 trips
