Let's solve your equation step-by-step.<span><span><span><span><span>− 14 </span>+ <span>6x </span></span>+ 7</span> −<span> 2x </span></span>=<span> 1 + <span>5x</span></span></span>
Step 1: Simplify both sides of the equation.<span><span><span><span><span>−14 </span>+ <span>6x </span></span>+ 7 </span>− <span>2x </span></span>=<span> 1 +<span> 5x</span></span></span><span>
Simplify: </span><span><span><span>4x - </span><span>7 </span></span>= <span><span>5x</span> + 1</span></span><span><span><span>4x</span> − 7</span>= <span><span>5x </span>+ 1</span></span>
Step 2: Subtract 5x from both sides.<span><span><span><span>4x</span> − 7</span> − <span>5x </span></span>= <span><span><span>5x </span>+ 1</span> −<span> 5x</span></span></span><span><span><span>− x </span>− 7 </span>=1 </span>
Step 3: Add 7 to both sides.<span><span><span><span>−x </span>− 7</span> + 7</span>=<span> 1+7</span></span><span><span>−x</span>=8</span>
Step 4: Divide both sides by -1.<span><span><span><span><span>−x/</span><span>−1 </span></span></span></span>=<span><span><span> 8/<span>−1</span></span></span></span></span><span>x=<span> −8</span></span>
Answer:<span>x= <span>−<span>8
hope this helps :)</span></span></span>
The domain of a function f(x) is the set of all values for which the function is defined, and the range of the function is the set of all values that f takes. A rational function is a function of the form f(x)=p(x)q(x) , where p(x) and q(x) are polynomials and q(x)≠0 .
the answer is graph b on edg.
Given:
Taking the LCM as 6,
Applying the product rule to 
:-
Now applying the product rule to 1/6:-
Hence, the answer.
AB = 30 in and BC = 50 in.
We use Pythagorean theorem to solve this. Since AN is an altitude, this means that it is perpendicular to BC. This means BN and AN are the legs of one right triangle, with AB being the hypotenuse:
18²+24² = AB²
324 + 576 = AB²
900 = AB²
Take the square root of both sides:
√900 = √AB²
30 = AB
NC and AN form the legs of the other right triangle, with AC being the hypotenuse:
24²+NC² = 40²
576 + NC² = 1600
Subtract 576 from both sides:
576 + NC² - 576 = 1600 - 576
NC² = 1024
Take the square root of both sides:
√NC² = √1024
NC = 32
BC = BN + NC = 18 + 32 = 50
