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SashulF [63]
3 years ago
9

Whats 0.2 divide by 0.4 work and answer

Mathematics
2 answers:
alexdok [17]3 years ago
3 0
Its is two since you take out the decimals then divide regularly
inn [45]3 years ago
3 0
The answer for 0.2 divide by 0.4 is 0.5. I hope this helps.
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In zoe's class, 4/5 of the students have pets. of the students who have pets, 1/8 have rodents. what fraction of the students in
olasank [31]
Let us assume the number of student's in Zoe's class = x
Then
Number of students that have pets = 4x/5
Number of students that have rodents as pets = (1/8) * (4x/5)
                                                                          = x/10
Number of students in Zoe's class
that have pets that are not rodents = (4x/5) - (x/10)
                                                         = (8x - x)/10
                                                         = 7x/10
I hope that the procedure is clear enough for you to understand and this is the answer that you were looking for.
8 0
3 years ago
Read 2 more answers
an office supply company sells two types of printers. they charge $95 for one of the printers and $125 for the other. if the com
Ivenika [448]

Answer:

22 of the 95$ ones and 10 of the 125

Step-by-step explanation:

22 times 95 = 2090

10 times 125 = 1250

2090+1250=3340

hope this helped

4 0
3 years ago
Mrs.Johnsons new car has an 18 gallon gas tank. If she can travel 400 miles on one tank of gasoline, what is her miles per gallo
serious [3.7K]

Answer:

22

Step-by-step explanation:

400/18=22.222222222

Round to 22

5 0
3 years ago
Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p
kvv77 [185]

The question is an illustration of composite functions.

  • Functions c(n) and h(n) are \mathbf{c(n) = 5000 + 250n} and \mathbf{n(h) = 5h}
  • The composite function c(n(h)) is \mathbf{c(n(h)) = 5000 + 1250h}
  • The value of c(n(100)) is \mathbf{c(n(100)) = 130000}
  • The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>

The given parameters are:

  • $5000 in fixed costs plus an additional $250
  • 5 systems in one hour of production

<u>(a) Functions c(n) and n(h)</u>

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

\mathbf{c(n) = Fixed + Additional \times n}

This gives

\mathbf{c(n) = 5000 + 250 \times n}

\mathbf{c(n) = 5000 + 250n}

The function for number of systems is:

\mathbf{n(h) = 5 \times h}

\mathbf{n(h) = 5h}

<u>(b) Function c(n(h))</u>

In (a), we have:

\mathbf{c(n) = 5000 + 250n}

\mathbf{n(h) = 5h}

Substitute n(h) for n in \mathbf{c(n) = 5000 + 250n}

\mathbf{c(n(h)) = 5000 + 250n(h)}

Substitute \mathbf{n(h) = 5h}

\mathbf{c(n(h)) = 5000 + 250 \times 5h}

\mathbf{c(n(h)) = 5000 + 1250h}

<u>(c) Find c(n(100))</u>

c(n(100)) means that h = 100.

So, we have:

\mathbf{c(n(100)) = 5000 + 1250 \times 100}

\mathbf{c(n(100)) = 5000 + 125000}

\mathbf{c(n(100)) = 130000}

<u>(d) Interpret (c)</u>

In (c), we have: \mathbf{c(n(100)) = 130000}

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0
3 years ago
Write the following number as ratios of integers
Grace [21]

We're going to "cut" the repeating part here in a few steps. First, we're going to put the number in a variable:

x=-2.0\overline{42}

Next, to get rid of the negative, we can multiply either side by -1 to get

-x=2.0\overline{42}

Now, we won't actually use this -x directly; instead, we want to create two new values, one by multiplying either side by 10:

-10x=20.\overline{42}

and the other by multiplying either side by 1000:

-1000x=2042.\overline{42}

Next, we can get rid of the repeated part of the number by subtracting -10x from -1000x:

-1000x-(-10x)=2042.\overline{42}-20.\overline{42}\\ -1000x+10x=2022\\ -990x=2022

And finally, we can divide either side of the equation by -990 to find that

x= \frac{2022}{-990}=-\frac{2022}{990}\div \frac{6}{6}=-\frac{337}{165}

5 0
3 years ago
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