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SashulF [63]
3 years ago
9

Whats 0.2 divide by 0.4 work and answer

Mathematics
2 answers:
alexdok [17]3 years ago
3 0
Its is two since you take out the decimals then divide regularly
inn [45]3 years ago
3 0
The answer for 0.2 divide by 0.4 is 0.5. I hope this helps.
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A triangle has height 15 in. and area 120 in. what is the lenght of its base?
nikklg [1K]
The base of the triangle measures 16 in.
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3 years ago
The volume of a cuboid is 32cm^2 Two of the lengths are 4cm and 2cm, what is the missing length?
andrew-mc [135]

Answer:

4 cm

Step-by-step explanation:

to find the volume you multiply the lengths of all three sides together:

let 'm' = missing side

32 = 4·2·m

32 = 8m

m = 4

5 0
3 years ago
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What is the area and perimeter of the figure below? The numbers are 3,3,3,3,4,2,2,5,2
RoseWind [281]
28 perimeter
12960 area
6 0
3 years ago
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
The length of a rectangle is 4 less than twice the width. The area of the
Zolol [24]

Answer:

Width: 7 Length: 10

Step-by-step explanation:

Width: x

length: 2x-4

Area: 70 meters squared

(2x-4)x=70

2x^2-4x=70

2x^2-4x-70=0

2(x^2-2x-35)=0

(x-7)(x+5)=0

x cannot be negative so x=7

8 0
3 years ago
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