Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
The slope is -3/2
Use the two ordered pairs (-2,0) and (0,-3) and do y2-y1/x2-x1
-3-0/0+2= -3/2
The set of real numbers for the equation x – 2 = √(2x – 1) will be 5.
<h3>What is the solution of the equation?</h3>
The solution of the equation means the value of the unknown or variable.
The equation is given below.
x – 2 = √(2x – 1)
Square on both side, then we have
(x – 2)² = 2x – 1
x² – 4x + 4 = 2x – 1
x² – 6x + 5 = 0
x² – 5x – x + 5 = 0
x(x – 5) – 1(x – 5) = 0
(x – 5)(x – 1) = 0
x = 1, 5
The set of real numbers for the equation x – 2 = √(2x – 1) will be 5.
More about the solution of the equation link is given below.
brainly.com/question/545403
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Answer:
Produce only Product B.
Step-by-step explanation:
The contribution margin per machine hour for product A is ...
($16 -$6)/(5 hour) = $2 per hour
The contribution margin per machine hour for product B is ...
($12 -$5)/(3 hour) ≈ $2.33 per hour
The company should produce the maximum possible number of the product that contributes the most per machine hour: Product B.