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Airida [17]
2 years ago
14

How to win a bey blade that stronger than you?

Mathematics
2 answers:
marishachu [46]2 years ago
6 0

Answer: The fact that beyblades spin at different speeds, you may want to get one that is fast while staying in control. Some have more mass than others leading them to spin slower, but the fact that they weigh so much may cause the other one to richochet off of it. Therefore get a big but fast beyblade that is very stable.

sveta [45]2 years ago
4 0

Answer:1. Takara Tomy Beyblade Burst B-148 Heaven Pegasus.

Step-by-step explanation:

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D) Pedro spends some of his money and at the end of the two
Ksenya-84 [330]

Answer:

it depend

Step-by-step explanation:

hopefully i help

5 0
3 years ago
True or false:<br> The solution, root, x-intercept, and zero of a problem are the same.
cluponka [151]
This is true . Solution , root , x and zero all are the same thing
3 0
3 years ago
Read 2 more answers
If ABCD is an A4 sheet and BCPO is the square, prove that △OCD is an isosceles triangle. And find the angles marked as 1 to 8 wi
Dmitry [639]

Answer:

The diagram for the question is missing, but I found an appropriate diagram fo the question:

Proof:

since OC = CD = 297mm Therefore, Δ OCD is an isoscless triangle

∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

∠DOP = 22.5°

∠PDO = 67.5°

∠ADO = 22.5°

∠AOD = 67.5°

Step-by-step explanation:

Given:

AB = CD = 297 mm

AD = BC = 210 mm

BCPO is a square

∴ BC = OP = CP = OB = 210mm

Solving for OC

OCB is a right anlgled triangle

using Pythagoras theorem

(Hypotenuse)² = Sum of square of the other two sides

(OC)² = (OB)² + (BC)²

(OC)² = 210² + 210²

(OC)² = 44100 + 44100

OC = √(88200

OC = 296.98 = 297

OC = 297mm

An isosceless tringle is a triangle that has two equal sides

Therefore for △OCD

CD = OC = 297mm; Hence, △OCD is an isosceless triangle.

The marked angles are not given in the diagram, but I am assuming it is all the angles other than the 90° angles

Since BC = OB = 210mm

∠BCO = ∠BOC

since sum of angles in a triangle = 180°

∠BCO + ∠BOC + 90 = 180

(∠BCO + ∠BOC) = 180 - 90

(∠BCO + ∠BOC) = 90°

since ∠BCO = ∠BOC

∴  ∠BCO = ∠BOC = 90/2 = 45

∴ ∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

For ΔOPD

Tan\ \theta = \frac{opposite}{adjacent}\\ Tan\ (\angle DOP) = \frac{87}{210} \\(\angle DOP) = Tan^-1(0.414)\\(\angle DOP) = 22.5 ^{\circ}

Note that DP = 297 - 210 = 87mm

∠PDO + ∠DOP + 90 = 180

∠PDO + 22.5 + 90 = 180

∠PDO = 180 - 90 - 22.5

∠PDO = 67.5°

∠ADO = 22.5° (alternate to ∠DOP)

∠AOD = 67.5° (Alternate to ∠PDO)

3 0
3 years ago
Please help im so confused asap
enyata [817]

Answer:

624

Step-by-step explanation:

the area of the triangles:

12*10 = 120

120/2 = 60

since there are 2 triangles of the same dimensions that make up the surface area 60 + 60 = 120

area of the rectangles:

13*14 = 182

since there are 2 rectangles of the same dimensions 182 + 182 = 364

The last rectangular:

10*14 = 140

add all areas:

120 + 364 + 140 = 624

8 0
2 years ago
Read 2 more answers
Solve for n 20 &gt; -4x - 8
yan [13]

Answer:

x > -7

Step-by-step explanation:

20 + 8 > -4x

Simplify

28 > -4x

Divide both sides by 4

-28/4 < x

-7 < x

x > -7

5 0
3 years ago
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