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marusya05 [52]
4 years ago
14

While John is traveling along a straight inter-

Physics
1 answer:
velikii [3]4 years ago
4 0

Answer:

Explanation:

The first displacement when the mile reading changes from 257 to 145

= 257 - 145

= 112 km

Then he turns back . This time the displacement will be negative .

The mile reading changes from 145 to 175

displacement = - ( 175 -  145 )

= - 30 km

Final displacement = 112 - 30

= 82 km .

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slava [35]

Answer:

The part of the Sun that you are observing is the photosphere . This appearance is called photosphere.

Explanation:

8 0
4 years ago
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Saturn's moon Mimas has an orbital period of 82,800 s at a distance of 1.87x10^8m from Saturn. Using m central m= (4n^2d^3/GT^2)
FromTheMoon [43]
5.65×10^26kg here you go
5 0
4 years ago
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Some car manufacturers claim that their vehicles could climb a slope of 42 ∘. For this to be possible, what must be the minimum
Paladinen [302]

Answer:

D. 0.9

Explanation:

Calculating minimum coefficient of static friction, we first resolve the forces (normal and frictional) acting on the vehicle at an angle to the horizontal into their x and y components. After this, we can now substitute the values of x and y components into equation of static friction. Diagrammatic illustration is attached.

Resolving into x component:

                        ∑F_{x} = F_{s} - mgsin\alpha =0

                          F_{s} = mgsin\alpha     ------(1)

Resolving into y component:

                        ∑F_{y} = F_{n} - mgcos\alpha =0

                          F_{n} = mgcos\alpha      ------(2)

Static frictional force, F_{s} \leq μ F_{n}       ------(3)

substituting F_{s} from equation (1) and F_{n} from equation (2) into equation (3)

                         mgsin\alpha \leq μ mgcos\alpha

                         sin\alpha \leq μ cos\alpha

                         μ \geq \frac {sin\alpha}{cos\alpha}

                         μ \geq tan\alpha

The angle the vehicles make with the horizontal α = 42°

                         μ ≥ tan 42°

                         μ ≥ 0.9

6 0
3 years ago
what nuclear fission and nuclear fusion have in common? A. They’re both used in power plants B. they have less mass than their r
arsen [322]

A. They’re both used in power plants . . . No.  

Nuclear fission is used in <u>all</u> nuclear power plants.  Fusion isn't used in <u>any</u> power plants yet, because we can't control it safely enough yet.  The only thing we can use nuclear fusion for is still bombs.

B. they have less mass than their reactants . . . No.  

Fission involves breaking atoms into pieces. Its products have less mass than its raw materials.  Fusion involves sticking atoms together to make new ones.  Its products have more mass than its raw materials.  Whatever the incomplete statement ' B ' is trying to say, it's not true of both processes.

<em>B. ==> </em> If you try really hard, this statement <em>(B)</em> can be undertood as true.  The TOTAL MASS after both a fission reaction and a fusion reaction is less than the total mass of whatever was fissled or fuzled.  In both cases, the missing mass is accounted for by the energy that was radiated from the site of the nuclear reaction.

But the statement in ' B ' is very poorly written.  When you read it, you don't know what 'they' refers to.  

C. they start with the same reactants . . . No.  

Man-made fission starts with the heaviest atoms ... Uranium and Plutonium.  Man-made fusion starts with the lightest atoms ... Hydrogen.

D. their products have more mass than their reactants ... No.

Fission breaks heavy atoms and makes lighter ones.  Fusion glues light atoms and makes heavier ones.

Gee whiz !  <em>None of the choices is correct. </em>

7 0
3 years ago
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Please help!<br> Drag and drop the words into the correct locations
Stells [14]

Answer:

background radiation

uniform

13700000000 years ago

7 0
3 years ago
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