Saturn's moon Mimas has an orbital period of 82,800 s at a distance of 1.87x10^8m from Saturn. Using m central m= (4n^2d^3/GT^2)
1 determine Saturn's mass.
Determine Saturn's mass by rearranging Newton's version of Kepler's Third Law.
2 answers:
Answer:
Explanation:
From Kepler's third law: Mass of the planet is given by:
where, T is the time period of satellite revolving about the planet at a distance d. G is the gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg²
Given, d = 1.87 × 10⁸ m
T = 82800 s
⇒
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