Your equation is: 5h + 4 = 10h + 8
First subtract 5h from both sides:(So that variable terms stays in one side only)
=> 5h + 4 -5h = 10h + 8 -5h
=> 4 = 5h + 8
Now subtract 8 from both sides:(So constant term stays in the opposite side of variable terms)
=> 4 - 8 = 5h + 8 - 8
=> -4 = 5h
Now divide both sides by 5:(division by coefficient of variable)
=> -4/5 = 5h/5
=> -4/5 = h
=> h = -4/5 = -0.8
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
It maybe will be ![\neq x^{2} \leq \\ \\ \int\limits^a_b {x} \, dx \int\limits^a_b {x} \, dx \sqrt{x} \\ \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. x^{2} x^{2} \sqrt{x} \lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \neq \sqrt{x} \sqrt[n]{x} \frac{x}{y} \frac{x}{y} \alpha \beta x_{123} \\ x^{2} \int\limits^a_b {x} \, dx x^{2}](https://tex.z-dn.net/?f=%5Cneq%20x%5E%7B2%7D%20%5Cleq%20%5C%5C%20%5C%5C%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%5Csqrt%7Bx%7D%20%5C%5C%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20x%5E%7B2%7D%20x%5E%7B2%7D%20%5Csqrt%7Bx%7D%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%5Cneq%20%5Csqrt%7Bx%7D%20%5Csqrt%5Bn%5D%7Bx%7D%20%5Cfrac%7Bx%7D%7By%7D%20%5Cfrac%7Bx%7D%7By%7D%20%5Calpha%20%5Cbeta%20x_%7B123%7D%20%5C%5C%20x%5E%7B2%7D%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20x%5E%7B2%7D)
Answer:
8 and 2/3 or 8.666666 forever
Step-by-step explanation:
