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prohojiy [21]
3 years ago
13

Can someone help me with this? Thank you!

Mathematics
1 answer:
satela [25.4K]3 years ago
3 0
The correct answer should be the third option. YOU'RE WELCOME :D
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Convert from general form to standard form x^2 + 4y^2 + 6x-40y+9 =0​
Burka [1]

x^2 + 4y^2 + 6x-40y+9 =0\\x^2 + 6x+9+4y^2-40y=0\\x^2+6x+9+4y^2-40y+100-100=0\\(x+3)^2+(2y-10)^2=100

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What is half of 90 ?
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PLeAsE sEnD hElP !!!!!!!!!!!!!!!!
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Answer:

5 units

Step-by-step explanation:

If DG, EG and FG are perpendicular bisectors of the sides of triangle ABC, then point G is the circumcenter of the triangle ABC and

BG = AG = CG as radii of the circumcirle.

Consider right triangle BEG. By the Pythagorean theorem,

BG^2=EG^2+BE^2\\ \\BG^2=4^2+3^2\\ \\BG^2 =16+9\\ \\BG^2=25\\ \\BG=5\ units

This gives us that

AG = BG = 5 units

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