4 × ( x + 4 ) = 3 × ( 3 + 5 )
4 × ( x + 4 ) = 3 × 8
Divide both sides by 4
x + 4 = 3 × 2
x + 4 = 6
Subtract both sides 4
x = 2
Bvgdgmhmgjm,jh,,,,,,,,,,,,,,,,,
A - 36 = B
B = 76 - A * 2.
the number is 40.
A = 40
:D
Well, I bet you want your answer right away! So here it is.
<span>Given <span>f (x) = 3x + 2</span> and <span>g(x) = 4 – 5x</span>, find <span>(f + g)(x), (f – g)(x), (f × g)(x)</span>, and <span>(f / g)(x)</span>.</span>
To find the answers, all I have to do is apply the operations (plus, minus, times, and divide) that they tell me to, in the order that they tell me to.
(f + g)(x) = f (x) + g(x)
= [3x + 2] + [4 – 5x]
= 3x + 2 + 4 – 5x
= 3x – 5x + 2 + 4
= –2x + 6
(f – g)(x) = f (x) – g(x)
= [3x + 2] – [4 – 5x]
= 3x + 2 – 4 + 5x
= 3x + 5x + 2 – 4
= 8x – 2
(f × g)(x) = [f (x)][g(x)]
= (3x + 2)(4 – 5x)
= 12x + 8 – 15x2 – 10x
= –15x2 + 2x + 8
<span>\left(\small{\dfrac{f}{g}}\right)(x) = \small{\dfrac{f(x)}{g(x)}}<span><span>(<span><span>g</span><span>f</span><span></span></span>)</span>(x)=<span><span><span>g(x)</span></span><span><span>f(x)</span></span><span></span></span></span></span><span>= \small{\dfrac{3x+2}{4-5x}}<span>=<span><span><span>4−5x</span></span><span><span>3x+2</span></span><span></span></span></span></span>
My answer is the neat listing of each of my results, clearly labelled as to which is which.
( f + g ) (x) = –2x + 6
( f – g ) (x) = 8x – 2
( f × g ) (x) = –15x2 + 2x + 8
<span>\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}<span><span>(<span><span>g</span><span>f</span><span></span></span>)</span>(x)=<span><span><span>4−5x</span></span><span><span>3x+2</span></span><span>
Hope I helped! :) If I did not help that's okay.
-Duolingo
</span></span></span></span>
Answer: B) 3+y+3
This can be simplified to y+6, but the current un-simplified expression has 3 terms.
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Explanation:
Terms are separated by a plus sign. If you had something like 10x-5y, then you would write that as 10x+(-5y) showing that 10x and -5y are the two terms.
Choices A and C, xy and 6y respectively, have one term each. They are considered monomials. Mono = one, nomial = name.
Choice D is the product of the constant 3 and the binomial y+3. Binomials have two terms.
Only choice B has three terms, though we can simplify it down to two terms. I have a feeling your teacher doesn't want you to simplify it.
