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3 years ago

Some1 Can Help me with this? I need the answer

Mathematics

1 answer:

bezimeni [28]3 years ago

8 0

It would be the second one from the top.
The reasoning is that when you have exponents of exponents you just multiply them and (8^12)^3 is just saying
(8^12)•(8^12)•(8^12) which when you are multiplying come number exponents you add the exponents which equals 8^36.

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PLEASE HELP ILL MARK U THE BRAINLIEST IT IS URGENT AND ITS GEOMETRY DONT WASTE ANSWERS PLEASE

Verdich [7]

Answer:

∠Q = ∠U = 60°

Step-by-step explanation:

Construct the figure QSUT with your own dimensions as long as QR ≅ RU and SR ≅ RT , where R is the common midpoint.

I choose QR = 4 cm and SR = 5 cm

Then measure ∠Q and ∠U to check if they are equal.

I got that ∠Q = ∠U = 60° proving that;

∠Q ≅ ∠U

6 0

3 years ago

What fractional part of a pound is an ounce

marysya [2.9K]

One ounce is one-sixteenth of a pound since there is 16 ounces in a pound.

6 0

4 years ago

Vector bought 15.6 pounds of paintballs. Ali together, the balls cost 35.99. About how much did the paintball cost per pound

Igoryamba

Answer:

<u>about $2.31 per pound</u>

Step-by-step explanation:

35.99/15.6 = 2.30705128205

2.31

Have a good day! :)

5 0

2 years ago

If you travel at a rate of 45 mph how many minutes will you will it take you to travel 1 mile

stiks02 [169]

It'd take you<span>, 1 minute and 33 secounds.
45 miles = 60 minutes
1 mile = 60/45 = 4/3 = 1.33 minutes </span>

7 0

3 years ago

Anyone knows how to do questions 7 and 8? 15 pts!!

Oksi-84 [34.3K]

7) Certainly there is a typo in the statement, just see that the expression of item (ii) is different from that of item (i). Probably the correct expression is: $2x^2-4x+5$ . With this consideration, we can continue.

(i) Let E the expression that we are analyzing:

$E=2x^2-4x+5\\\\ E=2x^2-4x+2-2+5\\\\ E=2(x^2-2x+1)-2+5\\\\ E=2(x-1)^2+3$

Since (x-1)² is a perfect square, it is a positive number. So, E is a result of a sum of two positive numbers, 2(x-1)² and 3. Hence, E is a positive number, too.

(ii) Manipulating the expression:

$2x^2+5=4x\\\\ 2x^2-4x+5=0$

So, it's the case when E=0. However, E is always a positive number. Then, there is no real number x that satisfies the expression.

8) Let E the expression that we want to calculate:

$E=(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)+1\\\\ E-1=(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)$

Multiplying by (2-1) in the both sides:

$(2-1)(E-1)=(2-1)(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ (E-1)=\underbrace{(2-1)(2+1)}_{2^2-1}(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ (E-1)=\underbrace{(2^2-1)(2^2+1)}_{2^4-1}(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ ...$ Repeating the process, we obtain: $...\\\\ E-1=(2^{32}-1)(2^{32}+1)\\\\ E-1=2^{64}-1\\\\ \boxed{E=2^{64}}$

3 0

4 years ago

Read 2 more answers