Answer:
The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Let 'S' be the sample space associated with the drawing of a card
n (S) = 52C₁ = 52
Let E₁ be the event of the card drawn being a king
Let E₂ be the event of the card drawn being a queen
But E₁ and E₂ are mutually exclusive events
since E₁ U E₂ is the event of drawing a king or a queen
<u><em>step(ii):-</em></u>
The probability of drawing of a king or a queen from a standard deck of playing cards
P( E₁ U E₂ ) = P(E₁) +P(E₂)
P( E₁ U E₂ ) = 
<u><em>step(iii):-</em></u>
The probability of drawing the compliment of a king or a queen from a standard deck of playing cards
<u><em>Conclusion</em></u>:-
The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846
Watch closely. I'll try to go slow:
You said <u>v² = 2 g t</u>
Divide each side by 2g : <em>v² / 2g = t</em>
Did you follow that ?
Answer:
f(x) = 16x2 + 32x - 9
To find the "zeros", set f(x) = 0:
0 = 16x2 + 32x - 9
The equation is solvable by factoring or by using the quadratic formula. The factors (use the "ac" method) are:
0 = (4x-1)(4x+9)
x = 1/4 = 0.25 and x = -9/4 = -2.25
Step-by-step explanation:
Answer:
She has $20 + $0.50n in her tip jar.
Step-by-step explanation:
Amount in tip jar at noon = $20
Average amount made from each customer = $0.50
Number of additional customers served after noon = n
Therefore, we have:
Additional amount made after noon = Average amount made from each customer * Number of additional customers served after noon = $0.50 * n = $0.50n
Amount in tip jar = Amount in tip jar at noon + Additional amount made after noon = $20 + $0.50n
Therefore, she has $20 + $0.50n in her tip jar.
Given:
Length = x + x + 3 = 2x + 3
Width = 2 + x
Area = length * width
91 ft² = (2x + 3) (2+x)
91 = 4x + 2x² + 6 + 3x
0 = 2x² + 7x + 6 - 91
0 = 2x² + 7x - 85
(2x + 17) ( x - 5)
x = -17/2 or x = 5
Let x = 5 ;
length = 2x + 3 = 2(5) + 3 = 13
width = 2 + x = 2 + 5 = 7
Area = 13 x 7 = 91
Perimeter = 2(length + width)
Perimeter = 2(13 + 7)
Perimeter = 2(20)
Perimeter = 20 feet of fencing
