Answer:
563.64 m
Explanation:
Given that as per the question
x = 5 cm = 0.05 m
D = 4.2 × 107 m
d = smallest aperture size
As per the situation the solution of the smallest aperture telescope that she can get away with is below :-
We will use Rayleigh's diffraction limit which is
The equation will be
![d\frac{0.05}{4.2\times 10^7} = 1.22[550\times 10^{-9}]](https://tex.z-dn.net/?f=d%5Cfrac%7B0.05%7D%7B4.2%5Ctimes%2010%5E7%7D%20%3D%201.22%5B550%5Ctimes%2010%5E%7B-9%7D%5D)
d = 563.64 m
So, the answer is d = 563.64 m
Answer:
"Planets May Affect the Chemistry of Their Stars. Planets are, by and large, at the mercy of their stars. Not only do stars provide a ready energy source of radiated light and heat, but the mass and gravitational pull of stars flat-out dwarfs the summed masses and pulls of any orbiting companions."
Answer: Energy is released by the electron in the form of light
Explanation:
Let's start by explaining that each atom in its natural state has a specific structure of its energy levels. Where <u>the lowest energy level is called the </u><u>ground state</u><u>. </u>
<u>
</u>
So, when an atom is in its ground state, its electrons fill the lower energy orbitals completely before they begin to occupy higher energy orbitals.
Then, when an atom is excited, it means that it has left its ground state (in which each electron occupies its place in its orbit, around the nucleus), when this happens some electron jumps out of the orbit it occupied in its fundamental state to an outer orbit, further away from the nucleus <u>and then return to the ground state, emitting in the form of light the energy received.</u>
To understand it better:
An excited electron is an unstable electron, and when passing from one orbit to another, it produces light of a specific wavelength (color) that depends on the amount of energy the electron loses.
Answer:A convex mirror produces an image which is half the
12cm in fro
Explanation:
which is half the size of the object placed at 12cm in front of it . Calculate the radius of curvature of thelf the size of the owhich is half the size of the object placed at 12cm in front of it . Calculate the radius of curvature of bject placed at 12cm in
