Answer:
1988 m
Explanation:
Range of a projectile
R = U²sin2∅/g...................... Equation 1
Where R = Range, U = Initial velocity, g = acceleration due to gravity, ∅ = Angle of projection.
Given: U = 150 m/s, ∅ = 60°
Constant: g = 9.8 m/s².
Substitute these values into equation 1
R = 150²(sin60°)/9.8
R = 22500(0.866)/9.8
R = 1988 m
Hence the Range of the projectile is 1988 m
It's hard to tell exactly what's happening in that 110 cm that you marked over the wave. What is under the ends of the long arrow ? How many complete waves ? I counted 4.5 complete waves ... maybe ?
If there are 4.5 complete waves in 110cm, then the length of 1 wave is (110/4.5)=24.44cm.
Frequency = speed/wavelength
Frequency = 2m/s /0.2444m
Frequency = 8.18 Hz
Answer:
h ’= 3.75 inch
Explanation:
For this exercise we use the definition of magnification which is the height of the image over the height of the object
m = h ’/ h
h’= m h
Let's calculate
h ’= 5 3/4
h ’= 3.75 inch
Sunlight is solar energy. It is considered a renewable resource because it can be used repeatedly and replaced naturally.
