Answer:
The fractional Intensity = 0.0146
Given:
wavelength of the light,
slit and screen separation difference, D = 130 cm = 1.3 m
distance of the point from the center of the principal maximum, y = 4.10 mm = 0.041 m
slit width, d = 0.420 mm =
Solution:
To calculate the fractional intensity, we use the given formula:
(1)
For very small angle:
(2)
where
Using eqn (2):
Now, using eqn (1):
π=iMRT
Where, π is Osmotic pressure,
i=1 for non-electrolytes,
M is molar concentration of dissolved species (units of mol/L)
R is the ideal gas constant = 0.08206 L atm mol⁻¹K⁻¹,
T is the temperature in Kelvin(K),
Here, to calculate M convert into standard units mg tog, ml to L, c to Kelvin
M= ( *10⁻³ )/ 0.175 =(5.987 *10⁻⁵)mol / 0.175L = 34.21*10⁻⁵ mol/L
π=iMRT=(1)*(34.21*10⁻⁵)*(0.08206)*(298.15)=837×10⁻⁵= 8.37×10⁻³ atm
=6.36 torr
(1 atm=760 torr, 1 Kelvin =273.15 °C, 1L=1000ml, 1g=1000mg)