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Setler [38]
3 years ago
5

1/2 (x−8)+1=2( 1 8 x−1)

Mathematics
1 answer:
nalin [4]3 years ago
7 0

Answer:

The solution for the given algebraic equation is \frac{ - 2}{71}

Step-by-step explanation:

Given algebraic equation as :

\frac{1}{2} ( x - 8 ) + 1 = 2 ( 18 x - 1 )

Now solving the equation while opening the brackets

So, \frac{1}{2} × x - \frac{1}{2} × 8  + 1 = 2 × 18 x - 2

Or, \frac{x}{2}  - \frac{8}{2}  + 1  = 36 x - 2

or,  \frac{x}{2}  - 4 + 1 = 36 x - 2

or,  \frac{x}{2}  - 3 = 36 x - 2

or,  \frac{x}{2} - 36 x = - 2 + 3

Or,  \frac{x}{2} - 36 x = 1

or, \frac{x - 72 x}{2} = 1

or, \frac{- 71 x}{2} = 1

∴ 71 x = - 2

I.e x = \frac{ - 2}{71}

Hence The solution for the given algebraic equation is \frac{ - 2}{71}    Answer

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The slope of a line can be stated many ways if not put into simplest form.
algol13

Answer:

slope is -3 or, so false

Step-by-step explanation:

5 0
3 years ago
Write the equation of the line with a slope of 2 that passes through the points -2,-7 and 5,7
lubasha [3.4K]

Answer:

Therefore the equation of the line through ( -2 , -7 ) and ( 5 , 7 ) is

2x - y = 3

Step-by-step explanation:

Given:

Slope = 2 = m ( say )

Let,

point A( x₁ , y₁) ≡ ( -2 , -7 )

point B( x₂ , y₂) ≡ ( 5 , 7 )

To Find:

Equation of Line AB =?

Solution:

Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula,

(y - y_{1} )=(\frac{y_{2}-y_{1} }{x_{2}-x_{1} })\times(x-x_{1}) \\

Or

Equation of a line passing through a points A( x₁ , y₁) and i having slope m is given by the formula,

(y - y_{1} )=m\times(x-x_{1}) \\

Substituting the given values in a above equation we get

(y-(-7))=2\times (x-(-2))\\ \\(y+7)=2(x+2)\\\\(y+7)=2x+4\\2x-y=3\\2x-y=3...............\textrm{which is the required equation of the line AB}

Therefore the equation of the line through ( -2 , -7 ) and ( 5 , 7 ) is

2x - y = 3

8 0
3 years ago
Que is on pic.i can't able to type in text.
ad-work [718]
It's not difficult to compute the values of A and B directly:

A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}
A=\tan^{-1}(\sin\theta)-\dfrac\pi4

B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt
B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}
B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2

Let's assume 0, so that |\csc\theta|=\csc\theta.

Now,

\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}
\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}
\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)
\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in A and B.
3 0
3 years ago
The triangles are similar. Find the value of x.
LUCKY_DIMON [66]

Answer: 95

Step-by-step explanation:

I am in geometry this year. We know by the AA thorem that all three angles are similar. Since both triangles have sides 45 and 40. We know that the last side has to 95.

Hope this helps :)

5 0
3 years ago
Read 2 more answers
Explain how to write 28% as a rate per 100
harkovskaia [24]
28% equals 28/100.  So, 28% equals 28 per 100.
8 0
3 years ago
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