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Setler [38]
3 years ago
5

1/2 (x−8)+1=2( 1 8 x−1)

Mathematics
1 answer:
nalin [4]3 years ago
7 0

Answer:

The solution for the given algebraic equation is \frac{ - 2}{71}

Step-by-step explanation:

Given algebraic equation as :

\frac{1}{2} ( x - 8 ) + 1 = 2 ( 18 x - 1 )

Now solving the equation while opening the brackets

So, \frac{1}{2} × x - \frac{1}{2} × 8  + 1 = 2 × 18 x - 2

Or, \frac{x}{2}  - \frac{8}{2}  + 1  = 36 x - 2

or,  \frac{x}{2}  - 4 + 1 = 36 x - 2

or,  \frac{x}{2}  - 3 = 36 x - 2

or,  \frac{x}{2} - 36 x = - 2 + 3

Or,  \frac{x}{2} - 36 x = 1

or, \frac{x - 72 x}{2} = 1

or, \frac{- 71 x}{2} = 1

∴ 71 x = - 2

I.e x = \frac{ - 2}{71}

Hence The solution for the given algebraic equation is \frac{ - 2}{71}    Answer

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Answer:

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Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 17 means that N = 17

4 are carrying nucleas weapons, which means that k = 4

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What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X > 1) = 1 - P(X \leq 1)

In which

P(X \leq 1) = P(X = 0) + P(X = 1)

So

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P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

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