=
=
Product = 12
Sum= 10
factoring;
2
2y(y+1)+10(y+1)=0
(2y+10)(y+1)=0
y=-1 or 2y=-10
y=-5
x=y+6
When y =-1
x=-1+6
x=5
when y =-5
x=-5+6
x=+1
Find the center and radius when x^2+y^2+4x-4y=17
2 answers:
Answer:
Center: (-2,2)
Radius:5
Step-by-step explanation:
The first step in this problem is to complete the square and to find the equation of this circle in standard form.
can be rearranged to be:
Now, you can begin to complete the square with both the x and the y:
Adding 8 to both sides and finishing the squares:
The coordinates of the center of the circle are (-2,2), and the radius is . Hope this helps!
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=
=
Product = 12
Sum= 10
factoring;
2
2y(y+1)+10(y+1)=0
(2y+10)(y+1)=0
y=-1 or 2y=-10
y=-5
x=y+6
When y =-1
x=-1+6
x=5
when y =-5
x=-5+6
x=+1
Answer: -287
Step-by-step explanation:
The given pattern: 9, 1, -7, -15, ….
We observe that ,
First term : a=9
Common difference between the terms= 1-9=-8
For Arithmetic sequence , the formula to find the nth term is given by :-
Then, 38th term will be :-
Hence, the 38th term of the sequence.= -287