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2 years ago

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Which is a better deal: 10 pounds of hamburger for $4.99 or 5 pounds of hamburger for $2.69? PLEASE HELP ME QUICKLY ILL LOVE YOU

FOREVER<33

2 answers:

JulijaS [17]2 years ago

7 0

Answer:

10 pounds for $4.99

Step-by-step explanation:

If you multiply the 5 pounds for 2.69 by 2, you would get 10 pounds of hamburger for 5.38 which is more than 4.99

Leviafan [203]2 years ago

5 0

10 pounds for 4.99
omg i need 20 characters but that’s the answer

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City A had a population of 10000 in the year 1990. City A’s population grows at a constant rate of 3% per year. City B has a pop

Georgia [21]

Answer:

City A and city B will have equal population 25years after 1990

Step-by-step explanation:

Given

Let

$t \to$ years after 1990

$A_t \to$ population function of city A

$B_t \to$ population function of city B

<u>City A</u>

$A_0 = 10000$ ---- initial population (1990)

$r_A =3\%$ --- rate

<u>City B</u>

$B_{10} = \frac{1}{2} * A_{10}$ ----- t = 10 in 2000

$A_{20} = B_{20} * (1 + 20\%)$ ---- t = 20 in 2010

Required

When they will have the same population

Both functions follow exponential function.

So, we have:

$A_t = A_0 * (1 + r_A)^t$

$B_t = B_0 * (1 + r_B)^t$

Calculate the population of city A in 2000 (t = 10)

$A_t = A_0 * (1 + r_A)^t$

$A_{10} = 10000 * (1 + 3\%)^{10}$

$A_{10} = 10000 * (1 + 0.03)^{10}$

$A_{10} = 10000 * (1.03)^{10}$

$A_{10} = 13439.16$

Calculate the population of city A in 2010 (t = 20)

$A_t = A_0 * (1 + r_A)^t$

$A_{20} = 10000 * (1 + 3\%)^{20}$

$A_{20} = 10000 * (1 + 0.03)^{20}$

$A_{20} = 10000 * (1.03)^{20}$

$A_{20} = 18061.11$

From the question, we have:

$B_{10} = \frac{1}{2} * A_{10}$ and $A_{20} = B_{20} * (1 + 20\%)$

$B_{10} = \frac{1}{2} * A_{10}$

$B_{10} = \frac{1}{2} * 13439.16$

$B_{10} = 6719.58$

$A_{20} = B_{20} * (1 + 20\%)$

$18061.11 = B_{20} * (1 + 20\%)$

$18061.11 = B_{20} * (1 + 0.20)$

$18061.11 = B_{20} * (1.20)$

Solve for B20

$B_{20} = \frac{18061.11}{1.20}$

$B_{20} = 15050.93$

$B_{10} = 6719.58$ and $B_{20} = 15050.93$ can be used to determine the function of city B

$B_t = B_0 * (1 + r_B)^t$

For: $B_{10} = 6719.58$

We have:

$B_{10} = B_0 * (1 + r_B)^{10}$

$B_0 * (1 + r_B)^{10} = 6719.58$

For: $B_{20} = 15050.93$

We have:

$B_{20} = B_0 * (1 + r_B)^{20}$

$B_0 * (1 + r_B)^{20} = 15050.93$

Divide $B_0 * (1 + r_B)^{20} = 15050.93$ by $B_0 * (1 + r_B)^{10} = 6719.58$

$\frac{B_0 * (1 + r_B)^{20}}{B_0 * (1 + r_B)^{10}} = \frac{15050.93}{6719.58}$

$\frac{(1 + r_B)^{20}}{(1 + r_B)^{10}} = 2.2399$

Apply law of indices

$(1 + r_B)^{20-10} = 2.2399$

$(1 + r_B)^{10} = 2.2399$ --- (1)

Take 10th root of both sides

$1 + r_B = \sqrt[10]{2.2399}$

$1 + r_B = 1.08$

Subtract 1 from both sides

$r_B = 0.08$

To calculate $B_0$ , we have:

$B_0 * (1 + r_B)^{10} = 6719.58$

Recall that: $(1 + r_B)^{10} = 2.2399$

So:

$B_0 * 2.2399 = 6719.58$

$B_0 = \frac{6719.58}{2.2399}$

$B_0 = 3000$

Hence:

$B_t = B_0 * (1 + r_B)^t$

$B_t = 3000 * (1 + 0.08)^t$

$B_t = 3000 * (1.08)^t$

The question requires that we solve for t when:

$A_t = B_t$

Where:

$A_t = A_0 * (1 + r_A)^t$

$A_t = 10000 * (1 + 3\%)^t$

$A_t = 10000 * (1 + 0.03)^t$

$A_t = 10000 * (1.03)^t$

and

$B_t = 3000 * (1.08)^t$

$A_t = B_t$ becomes

$10000 * (1.03)^t = 3000 * (1.08)^t$

Divide both sides by 10000

$(1.03)^t = 0.3 * (1.08)^t$

Divide both sides by $(1.08)^t$

$(\frac{1.03}{1.08})^t = 0.3$

$(0.9537)^t = 0.3$

Take natural logarithm of both sides

$\ln(0.9537)^t = \ln(0.3)$

Rewrite as:

$t\cdot\ln(0.9537) = \ln(0.3)$

Solve for t

$t = \frac{\ln(0.3)}{ln(0.9537)}$

$t = 25.397$

Approximate

$t = 25$

7 0

3 years ago

If x plus one upon X equal to 11 find the value of x square + 1 upon x square

zubka84 [21]

119 <answer (check the solution in above pic)

hey friend i hope this answer is helpful

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6 0

3 years ago

What is the equation of a line that is parallel to −3x+4y=4 and passes through the point (4,0)?

Genrish500 [490]

So you have to first put put the equation in slope-intercept form.
-3x+4y=4
+3x +3x
_______________
4y=4+3x
then you divide 4 by 4 and then divide 3x by 4 and you should get y=1+3/4x
then you plug in x and only x so that you can find y and then do the same once you find y
y=1+ (4)3/4
y= 1+3
y=4
then plug in y and solve for x
4= 1+ 3/4x
subtract 1 from both sides
3=3/4x
divide both sides by 3/4
and x=4
so then you find b and put it all in a equation.

3 0

3 years ago

Dharmesh has a square garden with the perimeter of 132 feet is the area of the garden greater than 1000 square feet

k0ka [10]

Yes, the area of the garden is greater than 1000 sq. ft.

132 = total perimeter
A square has 4 sides
132/4 = 33
A= LxW
A= 33 x 33
A= 1089 sq. ft.

7 0

3 years ago

a certain triangle has a perimeter of 3067 mi. the shortest side measures 71 mi less than the middle side and the longest side m

UkoKoshka [18]

Answer:

The measure of the shortest side is 851 miles

Step-by-step explanation:

Let

x ----> the measure of the shortest side

y ---> the measure of the middle side

z ---> the measure of the longest side

we know that

The perimeter of triangle is equal to

$P=x+y+z$

$P=3,067\ mi$

so

$3,067=x+y+z$ ----> equation A

the shortest side measures 71 mi less than the middle side

so

$x=y-71$ ----> equation B

the longest side measures 372 mi more the the middle side

so

$z=y+372$ ----> equation C

substitute equation B and equation C in equation A

$3,067=(y-71)+y+(y+372)$

solve for y

$3,067=3y+301\\3y=2,766\\y=922$

Find the value of x

$x=y-71\\x=922-71\\x=851$

therefore

The measure of the shortest side is 851 miles

6 0

2 years ago