Answer:
The answer to your question is the letter B. 5y³ - 18y² + 29y - 12
Step-by-step explanation:
Data
(y² - 3y + 4)(5y - 3)
Process
1.- Multiply the first terms by 5y
(y² - 3y + 4)(5y) = 5y³ - 15y² + 20y
2.- Multiply the first terms by -3
(y² - 3y + 4)(- 3) = -3y² + 9y - 12
3.- Simplify like terms
5y³ - 15y² + 20y -3y² + 9y - 12 = 5y³ + (-15y² - 3y²) + (20y + 9y) -12
4.- Result
= 5y³ - 18y² + 29y - 12
Your answer would be -11 :)
I hope this helps you
7×9×10.3
72×10.3
741.6
Answer:
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
Step-by-step explanation:
The height h of the ball is modeled by the following equation
The problem want you to find the times the ball will be 48 feet above the ground.
It is going to be when:
We can simplify by 16t. So
It means that
16t = 0
t = 0
or
t - 2 = 0
t = 2
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
If you input: 1/0.00000001 in a calculator, the result will be a very large number
so as you get closer to zero, the result of 1/x larger until it becomes infinite (or undefined as some people like to call it) at 1/0
