A rectangular pool has dimensions of 40ft and 60 ft. The pool has a patio
2 answers:
Could you finish the problem and tell us what the problem is
Answer:
Let
x-------> the width of the patio
we understand that
region of the pool=40*60-----> 2400 ft²
vicinity of the patio=[(40+2x)*(60+2x)]-2400
place of the patio=2400 ft²
so
[(40+2x)*(60+2x)]-2400=2400
2400+80x+120x+4x²-4800=0
4x²+200x-2400=0------> divide by 4 both sides----> x²+50x-600=0
therefore
the answer is
x²+50x-600=0
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C=8πab
Divide both sides by 8πb
c/(8πb) = a
Answer:
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Step-by-step explanation:
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