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DedPeter [7]
3 years ago
11

The furniture store sells each chair (c) for $225. To have them shipped to their house, the store charges $60. If the Browns bou

ght c number of chairs, how much did they spend (s)?​
Mathematics
1 answer:
11111nata11111 [884]3 years ago
6 0
<h3>Answer:      s = 225c+60</h3>

==========================================================

Explanation:

1 chair = 225 dollars

c chairs = 225c dollars .... multiply both sides by c

This shows that buying c chairs costs 225c dollars

c is a placeholder for a positive whole number

Add on the $60 shipping cost to get the total cost 225c+60

Therefore s = 225c+60

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Andrew is riding his bike. He biked a distance of 14 miles at a rate of 7 miles per hour. Using the distance formula, d = rt, so
rusak2 [61]

The computation shows that the time taken is 120 minutes.

<h3>How to illustrate the information?</h3>

From the information, Andrew is riding his bike and he biked a distance of 14 miles at a rate of 7 miles per hour.

Therefore, time taken for 14 miles will be:

= 14/7

= 2 hours

= 2 × 60 = 120 minutes

The time taken is 120 minutes.

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3 0
2 years ago
1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt
Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]

Given that

\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]

Let:

<em />L \to<em> Letters</em>

<em />C \to<em> Cost</em>

<em />

Using proportional reasoning, we have:

C  = kL

Where

<em />k \to<em> ratio of proportion</em>

For the first values of C and L, we have:

C  = kL

0.45 = k \times 10

Divide both sides by 10

k = 0.045

So, the equation of proportion is:

C = 0.045L

<u>When C = 6.75, we have:</u>

C = 0.045L

6.75 = 0.045L

Solve for L

L = \frac{6.75}{0.045}

L = 150

<u>When L = 7, we have:</u>

C = 0.045L

C = 0.045 \times 7

C = 0.315

<u>When L = 1, we have:</u>

C = 0.045L

C = 0.045 \times 1

C = 0.045

<u>When L = 500, we have:</u>

C =0.045L\\

C =0.045 \times 500

C =22.5

<u>When C = 18.90, we have:</u>

C = 0.045L

18.90 = 0.045L

Solve for L

L=\frac{18.90}{0.045}

L=420

Hence, the complete table is:

\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]

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3 years ago
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