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alekssr [168]
4 years ago
5

While Hadley was looking through her math textbook she came across the words "inverse operations", but couldn't remember what th

ey meant. In 2-3 complete sentences, remind Hadley what inverse operations are AND provide her with an example of how she can relate them to something in real life.
please help this is dew at 3:00??
Mathematics
1 answer:
egoroff_w [7]4 years ago
4 0

Answer:

Inverse operations are opposite operations that undo each other. Addition and subtraction are inverse operations. Multiplication and division are inverse operations.




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What is the constant of proportionality shown on the graph?
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Answer:

The constant of a proportionality in a graph of a proportional relationship is the constant ratio of y to x (the slope of the line

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Find the range and interquartille range for 13 12 15, 17, and 9,
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thse is the answer goog luck

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3 years ago
Does anyone know how to solve this problem!?
Sunny_sXe [5.5K]

Answer:

D.

Step-by-step explanation:

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3 years ago
Lesson 4.10 - Analytic Geometry
Nadusha1986 [10]

Geometric shapes are mathematical shapes that include squares and triangles

<h3>How to prove the shape is a square</h3>

The side lengths of a square are congruent, and the adjacent sides are perpendicular.

So, we start by calculating the side lengths using the following distance formula

d = \sqrt{(x_1 -x_2)^2 + (y_1 -y_2)^2}

Using the above formula, we have:

AB = \sqrt{(3-2)^2 + (4+2)^2} = \sqrt{37

BC = \sqrt{(2+4)^2 + (-2+1)^2} = \sqrt{37

CD = \sqrt{(-4+3)^2 + (-1-5)^2} = \sqrt{37}

DA = \sqrt{(-3-3)^2 + (5-4)^2} = \sqrt{37}

The above shows that the side lengths of the square are congruent.

Next, calculate the slope of the sides using:

m = \frac{y_2 -y_1}{x_2 -x_1}

So, we have:

m_{AB} = \frac{4 +2}{3 -2} = 6

m_{BC} = \frac{-2 + 1}{2+4} = -\frac 16

m_{CD} = \frac{-1 -5}{-4+3} = 6

m_{DA} = \frac{5 -4}{-3-3} = -\frac 16

Notice that the opposite slopes are congruent, and the adjacent slopes are opposite reciprocal.

The above highlight, and the equal side lengths show that the figure (1) is a square

<h3>How to prove the shape is a right isosceles triangle</h3>

The legs of a right isosceles triangle are congruent, and the legs are perpendicular.

So, we start by calculating the lengths of the legs using the following distance formula

d = \sqrt{(x_1 -x_2)^2 + (y_1 -y_2)^2}

Using the above formula, we have:

XY = \sqrt{(5-4)^2 + (-1-4)^2} = \sqrt{26

XZ = \sqrt{(5-0)^2 + (-1+2)^2} = \sqrt{26

The above shows that the legs of the right isosceles triangle are congruent.

Next, calculate the slope of the legs using:

m = \frac{y_2 -y_1}{x_2 -x_1}

So, we have:

m_{XY} = \frac{5-4}{-1 -4} = -\frac{1}{5}

m_{XZ} = \frac{5-0}{-1+2} = 5

Notice that the slopes are opposite reciprocal.

The above highlight, and the equal legs show that the figure (2) is a right isosceles triangle

Read more about geometric shapes at:

brainly.com/question/14285697

7 0
3 years ago
Pre-calc<br> x - 3 is a factor of P(x) = x^3 – 7x² +15x-9<br> A. True<br> B. False
joja [24]
A. True
Explanation-

Let p(x) = x^3 – 7x^2 – 15x – 9

For checking that (x – 3) is a factor of p(x), we find : p(3)

p(3) = (3)^3 – 7(3)^2 + 15(3) – 9

= 27 – 63 + 45 – 9

= 72 – 72

= 0

Hence, (x – 3) is a factor of p(x).

By division of p(x) by x – 3, we get the quotient

= x^2 – 4x + 3

∴ x^3 – 7x^2 + 15x – 9

= (x – 3)(x^2 – 4x + 3)

= (x – 3)(x – 3)(x – 1)

= (x – 3)^2(x – 1)
4 0
2 years ago
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