Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:

Compute the sample size as follows:

![n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 60}{2}]^{2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%2060%7D%7B2%7D%5D%5E%7B2%7D)

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Answer:
it is B
Step-by-step explanation:
4a - 3b
4(5) - 3(- 2)
20 + 6
26
26 is your answer.
Answer:
802,000
Step-by-step explanation:
The number in the thousands place is 1, and the number to the right of it is 5. And if the number to the right is greater than or equal to 5 the place value that you are rounding goes up by one.
Answer: A. 370 cm2
Step by Step explanation:
10x15=150 The big rectangle
15x6=90x2=180 The small rectangles
20x2=40 the triangles
Add all up 150+180+40=370
Hope this helped